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Licemer1 [7]
3 years ago
5

What is 78,000,000 in scientific notation

Mathematics
2 answers:
Sergio [31]3 years ago
7 0
Hi!

Solution:

1. You have to move the decimal point until you have a number that is between 1 and 10.

2. Then add a power of 10, which would tell you how many decimal places you moved.

_______________________________

In your case:

78,000,000 —> you would move the

decimal point 7 times to the left and

your new number will be 7.8 ( which is

between 1 and 10.


Since you moved 7 places to the left,

your power of 10 will be 10^7 or 10 to the

7th power.


Your Answer: 7.8 x 10^7

Hope this helps!
fomenos3 years ago
3 0

Answer:

7.8×10⁷

Step-by-step explanation:

You want to keep the coefficient (7.8) between 1 and 10 to achieve a normalized notation. Otherwise 78×10⁶ would also be an option.

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nata0808 [166]

Answer:

-3a-12

Step-by-step explanation:

3(-2a-4)+3a

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3 0
2 years ago
Plz help I’ll mark you
timurjin [86]

Answer:

A 1/2

Step-by-step explanation:

Ratio of short length to hypotenuse

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4 0
3 years ago
Choose the point-slope form of the equation below that represents the line that passes through the points (-6, 4) and (2, 0).
Arte-miy333 [17]
Point slope form
y-y1=m(x-x1)
slope=m
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given
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slope=(0-4)/(2-(-6))=-4/(2+6)=-4/8=-1/2

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not listed
5 0
3 years ago
What is the remainder of (4x2 + 7x-1)= (4 + x)?<br>A. -9x – 1<br>B.23x – 1<br>C.35<br>D.-37​
bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\

Step-by-step explanation:

\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}

\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\

\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}

6 0
3 years ago
Read 2 more answers
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alina1380 [7]

Answer: A, C, B

Step-by-step explanation:

Because "a" has 8 across

And "c" has 10 across

and "b" has 13 across

7 0
3 years ago
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