Help me please will give brainliest
2 answers:
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Answer:
Step-by-step explanation:
We want to solve the equation:
In the interval [0, 2π).
Notice that this is in quadratic form. Namely, by letting u = sin(θ), we acquire:
Factor:
By the Zero Product Property:
Solve for each case:
Back-substitute:
Use the Unit Circle. Hence, our three solutions in the interval [0, 2π) are:
Answer:
Problem 1:
a. x=2
b. x=3
c. x=1
Problem 2:
A multiplication equation to hold the table true:
A division equation to hold the table true:
Step-by-step explanation:
Given in problem 1:
(a). The equation is
It holds true for all values of .
Let us say ,
which is greater than 1.
(b). The equation is
It holds true for all values of .
Let us say
which is less than 1.
(c). The equation is
It holds true for only .
Let us say ,
which is equal to 1.
Problem 2:
A multiplication equation to hold the table true:
A division equation to hold the table true:
Therefore these are the values which hold true to the equation in problem 1 and 2.
