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Luda [366]
4 years ago
13

What is an Acid? need help..

Chemistry
2 answers:
Rasek [7]4 years ago
8 0
An acid is a substance that can dissolve some metals, break apart in water, and has a pH below 7. Acid taste bitter and can react with some bases to form salts. Acids turn litmus paper red.

Some acids, like Coca-Cola or Vinegar are harmless while some, like stomach acid, aren't so harmless. 
Sonja [21]4 years ago
4 0
Acid is a substance that can desolve some metals
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Answer:

Since energy can’t be created or destroyed, and water loses potential energy when it freezes to form ice. The energy remains electrical but then changes to kinetic when Enough energy is released.

Explanation:

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Equilibrium systems exist throughout nature.<br> True or False??
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17.<br> What do you know about a chemical compound by looking at its chemical formula
Bas_tet [7]

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The number and the kinds of atoms in the compound

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5 0
4 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
4 years ago
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