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vazorg [7]
3 years ago
6

How are exothermic reactions different from endothermic reactions?

Chemistry
1 answer:
Ostrovityanka [42]3 years ago
3 0
Reactions which emits energy in the form of light or heat are called exothermic reactions.

reactant(s) -------------->  product(s) + heat

Reactant which absorbs energy in the form of heat or light are called endothermic reactions.

reactant(s) + heat -----------> product(s)

Hope this helps!

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Please help me with chemistry!! with explanation so i can understand and further the knowledge
iren [92.7K]
Density= mass/volume aluminum can= 174 •g/ 4 • cm ^3. =2.76•g•cm ^-3
6 0
3 years ago
TRUE or FALSE<br> Nonpolar molecules only have nonpolar bonds.
Kitty [74]

Answer:

its false

Explanation:

srry if its wrong ;-;

4 0
2 years ago
What is the definition of an atomic radius
chubhunter [2.5K]

Answer:

iIllustrated Glossary of Organic Chemistry - Atomic radius. Atomic radius: The radius of an atom. This distance between an atom's nucleus and outer electron shell. ... Atomic radius differs with the bonding state of an atom (for example an nonbonded atom of an element versus the same element within a covalent bond).

5 0
3 years ago
he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
wolverine [178]

1) Drift velocity: 3.32\cdot 10^{-4}m/s

2) 5.6\cdot 10^{13} electrons per person

Explanation:

1)

For a current flowing through a conductor, the drift velocity of the electrons is given by the equation:

v_d=\frac{I}{neA}

where

I is the current

n is the concentration of free electrons

e=1.6\cdot 10^{-19}C is the electron charge

A is the cross-sectional area of the wire

The cross-sectional area can be written as

A=\pi r^2

where r is the radius of the wire. So the equation becomes

v_d=\frac{I}{ne\pi r^2}

In this problem, we have:

I = 8.0 A is the current

8.5\cdot 10^{28} m^{-3} is the concentration of free electrons

d = 1.5 mm is the diameter, so the radius is

r = 1.5/2 = 0.75 mm = 0.75\cdot 10^{-3}m

Therefore, the drift velocity is:

v_d=\frac{8.0}{(8.5\cdot 10^{28})(1.6\cdot 10^{-19})\pi(0.75\cdot 10^{-3})^2}=3.32\cdot 10^{-4}m/s

2)

The total length of the cord in this problem is

L = 3.00 m

While the cross-sectional area is

A=\pi r^2=\pi (0.75\cdot 10^{-3})^2=1.77\cdot 10^{-6} m^2

Therefore, the volume of the cord is

V=AL (1)

The number of electrons per unit volume is n, so the total number of electrons in this cord is

N=nV=nAL=(8.5\cdot 10^{28})(1.77\cdot 10^{-6})(3.0)=4.5\cdot 10^{23}

In total, the Earth population consists of 8 billion people, which is

N'=8\cdot 10^9

Therefore, the number of electrons that each person would get is:

N_e = \frac{N}{N'}=\frac{4.5\cdot 10^{23}}{8\cdot 10^9}=5.6\cdot 10^{13}

7 0
4 years ago
Solid iron reacts with aqueous copper(II) sulfate
Tatiana [17]

Answer :

Fe(s) + CuSo4(aq) arrow Cu(s) +FeSo4(aq)

5 0
3 years ago
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