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3 years ago

How many grams of hydrogen chloride can be produced from 1.00g of hydrogen and 55.0g of chlorine? what is the limiting reactant?

Chemistry

1 answer:

zloy xaker [14]3 years ago

4 0

Answer:

$m_{HCl}=36.1gHCl$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required grams of HCl by firstly identifying the limiting reactant via the moles of each reactant as they are in a 1:1 mole ratio:

$n_{H_2}=1.00gH_2*\frac{1molH_2}{2.02gH_2}=0.500molH_2\\\\ n_{Cl_2}=55.0gCl_2*\frac{1molCl_2}{70.9gCl_2}=0.776molCl_2$

Thus, we infer the hydrogen is the limiting reactant and therefore we use its 1:2 mole ratio with HCl whose molar mass is 36.46 g/mol:

$m_{HCl}=0.500molH_2*\frac{2molHCl}{1molH_2}*\frac{36.46gHCl}{1molHCl}\\\\m_{HCl}=36.1gHCl$

Regards!

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The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co

garri49 [273]

Answer:

There are $5.408\times 10^{22}$ grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater ( $m_{sw}$ ), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

$m_{sw} = \rho_{sw}\cdot V_{sw}$

Where:

$\rho_{sw}$ - Density of seawater, measured in grams per liters.

$V_{sw}$ - Volume of seawater, measured in liters.

If $V_{sw} = 1.5\times 10^{21}\,L$ and $\rho_{sw} = 1030\,\frac{g}{L}$ , then:

$m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)$

$m_{sw} = 1.545\times 10^{24}\,g$

The total mass of sodium chloride is determined by the following ratio:

$r = \frac{m_{NaCl}}{m_{sw}}$

$m_{NaCl} = r\cdot m_{sw}$

Given that $m_{sw} = 1.545\times 10^{24}\,g$ and $r = 0.035$ , the total mass of sodium chloride in all the seawater in the world is:

$m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)$

$m_{NaCl} = 5.408\times 10^{22}\,g$

There are $5.408\times 10^{22}$ grams contained in all the seawater in the world.

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4 years ago

A cold can of soda is taken out of the refrigerator. It slowly warms up until it is at room temperature. Once the soda has warms

lara31 [8.8K]

Answer:

See explanation

Explanation:

We know that the thermal energy of a substance largely depends on the temperature of the body. This implies that the hotter a substance is, the greater its thermal energy and vice versa.

When you bring a cold can of soda out of the refrigerator, the molecules of air at room temperature gradually loose energy to the can and condense around it. This transfers thermal energy from the air particles to the molecules in the cold can of soda and the soda warms up pretty soon!

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3 years ago

If i mix nuts and bananas and raisins without cooking them , is this a physical or chemical change

defon

Answer: physical

Explanation: you have not cooked them so nothing has happened

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A painted turtle is a cold blooded animal that often sits on a log and basks in the sun. Why might it do this?

Pavlova-9 [17]

Cold blooded animals are not warm themselves, so they use the energy from the sun to get warm.

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Using the equation below, calculate the number of grams of CO that can react completely with 78.9 g Fe2O3

yulyashka [42]

Answer:

41.51 g of CO

Explanation:

The balance chemical equation for given double displacement reaction is,

Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

Step 1: Calculate moles of Fe₂O₃:

Moles = Mass / M.Mass

Moles = 78.9 g / 159.68 g/mol

Moles = 0.494 moles

Step 2: Calculate moles of CO:

According to equation,

1 mole of Fe₂O₃ reacted with = 3 moles of CO

so,

0.494 moles of Fe₂O₃ will react with = X moles of CO

Solving for X,

X = 0.494 mol × 3 mol ÷ 1 mol

X = 1.482 moles of CO

Step 3: Calculate Mass of CO as:

Mass = Moles × M.Mass

Mass = 1.482 mol × 28.01 g/mol

Mass = 41.51 g of CO

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