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Anon25 [30]
3 years ago
13

In the function y+3=(1/3x)^2+1 what effect does the number 1/3 have on the graph as compared to the graph of y=x^2

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0

Answer:

what graph?

Step-by-step explanation:

i cant help unless a see a screen shoot?

Alex787 [66]3 years ago
5 0

Answer:

I think the answer is

B. it stretches the graph horizontally by a factor of 3

Step-by-step explanation:

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The perimeter of a triangle is 39 feet. One side of the triangle is one foot longer than the second side. The third side is two
Ivenika [448]

Answer:

Step-by-step explanation:

39 feet for one side

40 feet for another

42 feet for the last side

I got the answer by adding 1 foot to the first side which comes out to be 40 feet, I got the last answer by adding 2 feet to 40 which is 42.

3 0
3 years ago
A restaurant has fixed costs of $147.50 per day and an average unit cost of $5.75 for each meal served. If a typical meal costs
Nikolay [14]

Answer:

The answer is 118.

Step-by-step explanation:

First we need to subtract the meal cost from average unit cost for each meal:

7-5.75=1.25

A restaurant profits 1.25$ for each meal. If we divide fixed cost to profit for each meal:

147.5/1.25=118

The restaurant have to sell 118 meals at least each day for the owner to break even

5 0
3 years ago
Which of the following are exterior angles? Check all that apply.
3241004551 [841]
Angles 4, 6, and 2. Pls mark me brainliest. And have a great life ahead! If you mark me brainliest, it will really make me happy. Thank you so much!
6 0
2 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
PLEASE HELP WITH QUESTIONS 4 AND 5
agasfer [191]

Answer:

4 - Complementary

5 - Supplementary

Step-by-step explanation:

i can't find the value of X

6 0
3 years ago
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