What is the osmotic pressure of a solution made by dissolving 60.0 g of glucose, C₆H₁₂O₆, in enough water to form 800.0 mL of so
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The answer for the following problem is mentioned below.
- <u><em>Therefore the final temperature of the gas is 740 K</em></u>
Explanation:
Given:
Initial pressure of the gas () = 1.8 atm
Final pressure of the gas () = 4 atm
Initial temperature of the gas () = 60°C = 60 + 273 = 333 K
To solve:
Final temperature of the gas ()
We know;
From the ideal gas equation;
we know;
P × V = n × R × T
So;
we can tell from the above equation;
<u> P ∝ T</u>
(i.e.)
<em> </em><em> = constant</em>
=
Where;
= initial pressure of a gas
= final pressure of a gas
= initial temperature of a gas
= final temperature of a gas
=
=
= 740 K
<u><em>Therefore the final temperature of the gas is 740 K</em></u>