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valentinak56 [21]
3 years ago
15

Explain what happens if the nucleus, of an atom, becomes unstable.

Chemistry
2 answers:
Ainat [17]3 years ago
4 0

Answer:The unstable nucleus of radioactive atoms emit radiation. When this occurs, a new atom and element are formed. This process is called radioactive decay. It continues until the forces in the unstable nucleus are balanced.

Explanation:

Gelneren [198K]3 years ago
3 0

Answer:

The unstable nucleus of radioactive atoms emit radiation. When this occurs, a new atom and element are formed. This process is called radioactive decay. It continues until the forces in the unstable nucleus are balanced.

Explanation:

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82.0343 g/mol

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Count each element and the number of atoms for each element. Add them all together. Use the periodic table.

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Why is Earth's surface rarely impacted by large objects that enter Earth's 13 points
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A.Because Earth's atmosphere causes most objects to burn up before they reach the  surface.

Explanation:

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Why do we fill balloons with helium gas instead of oxygen gas
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4 years ago
How are the formulas for ionic and covalent compounds determined?
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Writing Formulas of Ionic Compounds

The cation is written first, followed by the monatomic or polyatomic anion. The subscripts in the formula must produce an electrically neutral formula unit.

8 0
3 years ago
Read 2 more answers
When 38^88Sr decays to 34^84Kr, a(n) ______________ is emitted
navik [9.2K]

Answer:

The correct answer is - alpha particle and positron.

Explanation:

In this question, it is given that, 38^88Sr decays to 34^84Kr, which means there is an atomic number decrease by 4, 38 to 34, and atomic mass decreases by 4 as well 88 to 84.

A decrease in the atomic mass is possible only when there is an emission of the alpha particle as an alpha particle is made of 2 protons and 2 neutrons. If an atom emits an alpha particle, there is a change in atomic number as it decreases by two, and its mass number decreases by four.

So after the emission of an alpha particle, the new atom would be

38^88Sr=> 36^84X => 34^84Kr

so there is also two positron emission that leads to decrease in atomic number by one with each emission:

38^88Sr=> 2^4He+ 36^84X => 36^84X + 2(1^0β+) => 34^84Kr

Positron decay is the conversion of a proton into a neutron with the emission of a positron that causes the atomic number is decreased by one, which causes a change in the elemental identity of the daughter isotope.

3 0
3 years ago
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