Answer:
frequency of allele “A” is .39
frequency of allele “a” is .77
Explanation:
hardy weinberg equation
p^2 + 2pq + q^2 = 1 or (A+a)^2
p^2 = (AA)
2pq = (Aa)
q^2 = (aa)
AA -> 15/100 = .15
Aa -> 25/100 = .25
aa -> 60/100 = .60
if p^2 = AA = .15 then A = √.15 = 0.38729833462 = .39
if q^2 = aa = .60 then a = √.60 = 0.77459666924 = .77
wikipedia quoraAnkitGauba
D.) ovary oviduct uterus then vagina
Answer:
A - DNA
B - mRNA
C - nuclear pore
D - tRNA
E - ribosome
F - rRNA
Explanation:
<em>The entire structure illustrates the process of transcription and translation in a typical eukaryotic cell.</em>
The DNA (A) in the nucleus of the cell is first transcribed to mRNA (B). The mRNA produced is transported to the cytoplasm through the openings within the nuclear membrane - the nuclear pores (C). On getting to the cytoplasm, the mRNA binds to the ribosome (E) (carrying rRNA, F). The tRNA (D) carrying the specific anticodon for a particular codon on the mRNA then binds to the structure and the corresponding amino acid is released. A polypeptide bond is formed between subsequent amino acids and the ribosome moves along the mRNA chain until the translation process is complete.
Answer:
Negatively repressible.
Explanation:
A control which occurs through repressor is known as negative control which may be inducible or repressible.
When a small molecule named as allolactose binds this repressor it leads to allosteric repulsion which removes repressor from the operator as a result of which RNA polymerase can start transcription. Allolactose is therefore known as inducer because it induces lac operon expression.
But here, the operator is active (induced) already so there is no need to induce the operon which means that it can only be repressed so that transcription could stop. So the answer is negatively repressible operon.
I think BO or B, but BO has more chance.
