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vodka [1.7K]
3 years ago
6

Pls help w this stoichiometry question i can’t figure it out thanks sm

Chemistry
1 answer:
notka56 [123]3 years ago
5 0

Answer: 6.3x10-² moles of H20

Explanation: Solution:

Convert first the mass of O2 to moles which is 1 mole of O2 over its molar mass. The molar mass of O2 is 32. Then after that check the stoichiometric factors of both O2 and H2O.

0.252gO2 x 1mole O2/ 32 g O2 x 4 mol H2O/ 5 moles O2.

Both g of O2 and moles of O2 will be canceled out so the remaining unit is mole of H2O.

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In the given molecule XeH_4, 'Xe' is the central atom and 'H' is the terminal atom.

Xenon has 8 valence electrons and hydrogen has 1 valence electron. Therefore, the total number of valence electrons are 8 + 4(1) = 12 electrons.

The number of electrons used in Xe-H bonding = 8 electrons

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There are 4 bonding pairs and 2 lone pairs of electrons, they will be arranged in the octahedral arrangement around the central atom with 2 lone pairs of electrons on central atom. The lone pairs are arranged linearly across the central atom. The resulting structure will be square-planar.

The structure of XeH_4 is shown below.

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3 years ago
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