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vodka [1.7K]
3 years ago
6

Pls help w this stoichiometry question i can’t figure it out thanks sm

Chemistry
1 answer:
notka56 [123]3 years ago
5 0

Answer: 6.3x10-² moles of H20

Explanation: Solution:

Convert first the mass of O2 to moles which is 1 mole of O2 over its molar mass. The molar mass of O2 is 32. Then after that check the stoichiometric factors of both O2 and H2O.

0.252gO2 x 1mole O2/ 32 g O2 x 4 mol H2O/ 5 moles O2.

Both g of O2 and moles of O2 will be canceled out so the remaining unit is mole of H2O.

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When looking at flat-tailed horned lizards, what trait was found in most living lizards compared to dead lizards? *
UkoKoshka [18]

Answer:

d after any reptile that is poisinis when it dies the amount of poisin becoms weaker becuase its rrying to kill air but it kill nothing

Explanation:

5 0
3 years ago
Read 2 more answers
Consider the equilibrium: HCOOH(aq) + F-(aq) <----> HCOO-(aq) + HF (aq) Given that the Ka of HCOOH = 1.8 x 10-4 and the Ka
Aleks [24]

Hey there!:

K = Ka * Kb / Kw

Ka = 1.8*10⁻⁴

Kb = 10⁻¹⁴ / 6.8*10⁻⁴

K =  1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )

K =  = 1.8 / 6.8

K = 0.265

Answer A

Therefore:

K is less than on the forward reaction is not favorable .


Hope That helps!

8 0
3 years ago
A sample of pure oxalic acid (H2C2O4.2H2O) weighs 0.2000 g and requires 30.12 ml of KOH solution for
ValentinkaMS [17]

 The molarity  of KOH  is  0.1055 M

 <u><em> calculation</em></u>

Step  1: write  the  equation  for reaction between H₂C₂O₄.2H₂O  and KOH

H₂C₂O₄.2H₂O  + 2 KOH   →    K₂C₂O₄ +4 H₂O

step 2: find the moles  of H₂C₂O₄.2H₂O

moles = mass÷ molar  mass

from  periodic  table the  molar mass H₂C₂O₄.2H₂O= (1 x2) +(12 x2) +(16 x4)  + 2(18)=126 g/mol

 = 0.2000 g ÷ 126 g/mol =0.00159  moles


step 3: use the  mole  ratio  to  calculate the moles of KOH

H₂C₂O₄.2H₂O : KOH  is 1:2

therefore the  moles of KOH  =0.00159 x 2 = 0.00318  moles

step 4: find molarity of KOH

molarity = moles/volume in liters

volume in liters = 30.12/1000=0.03012 L

molarity  is therefore = 0.00318/0.03012 =0.1055 M

5 0
3 years ago
Data can be arranged in visual displays called
mojhsa [17]
Data can arranged into visual displays called graphs. There are multiple types of graphs such as bar graphs, line graphs, scatter plots, and pie charts.

hopefully this helps :)
4 0
3 years ago
If there is a loss of 5.63 x 10-7kg of mass in a nuclear reaction, how many Joules of energy would be released? Recall that c =
Fudgin [204]
Thank you for posting your question here at brainly. 

E = mc^2 
<span>where E is the energy in joules, </span>
<span>m is the mass in kilograms, </span>
<span>and c is the speed of light. </span>

<span>E = mc^2 </span>
<span>E = (5.63 x 10^-7 kg)(3 x 10^8 m/s)^2 </span>
<span>E = 5.07 x 10^10 J </span>


5 0
3 years ago
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