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Fittoniya [83]
3 years ago
6

Why are metals electropositive in nature​

Chemistry
1 answer:
Mariana [72]3 years ago
7 0

Answer:

The tendency of metals to lose electrons inorder to get stability is called electropositive nature ofmetals. In general most of the metalslose electrons from their valence shell due to weak force of attraction on the outermost shell.

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It’s D I am pretty sure.
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Calculate the PE of an object that has a mass of 2kg that is resting on a 6m table. HELP ME PLEASE I REALLY NEEEEED HELP!!!! 21
Sergeeva-Olga [200]

Answer:

Calculate the unknown variable in the equation for gravitational potential energy, where potential energy is equal to mass multiplied by gravity and height; PE = mgh. Calculate for different gravity of different enviornments - Earth, the Moon, Jupiter, or specify your own. Free online physics calculators, mechanics, energy, calculators.

Explanation:

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6) Which of these elements is a metal?<br> E) C<br> D) N<br> A) O<br> C) Ne<br> B) Ca
sertanlavr [38]

Answer:

Ca

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It is on the left side of the periodic table where metals are located.

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Read 2 more answers
14. Which of the following is produced when propane (C3H8) is combusted completely? (2 points)
Ymorist [56]

The following is produced when propane (C₃H₈) is combusted completely : H₂O

<h3>Further explanation  </h3>

Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.  

If O₂ is insufficient there will be incomplete combustion produced by CO and H and O  

Hydrocarbon combustion reactions (especially alkanes)  \large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}

For combustion of propane C₃H₈ (n = 3) ⇒ completely(excess O₂) :

C₃H₈+5O₂⇒3CO₂+4H₂O

The products of combustion : CO₂ and H₂O

7 0
3 years ago
Acetic acid and water react to from hydronium cation and acetate anion, like this: HCH3CO2 (aq) + H2O (I) → H3O+(aq) + Ch3CO2-(a
Roman55 [17]

Answer:

1) Greater than zero, and equal to the rate of the reverse reaction

2) Greater than zero, but less than the rate of the reverse reaction

3) Greater than zero, and equal to the rate of the reverse reaction

Explanation:

A reaction system is said to be in equilibrium when the rate of forward reaction is equal to the rate of reverse reaction.

Before we remove HCH3CO2 from the system, the system was in equilibrium. Recall that when a system is in equilibrium, the rate of forward reaction is equal to the rate of reverse reaction. The rate of reaction is greater than zero because products are being formed as the reactants interact with each other.

When HCH3CO2 is removed from the system, the equilibrium position shifts towards the left hand side hence the rate of reverse reaction is greater than the rate of forward reaction.

When the system attains equilibrium again, the rates of forward and reverse reaction become equal.

8 0
3 years ago
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