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AleksAgata [21]
4 years ago
10

A restaurant offers 77 possible​ appetizers, 1515 possible main​ courses, and 99 possible desserts. how many different meals are

possible at this​ restaurant? ​ (two meals are considered different unless all three courses are the​ same).
Mathematics
1 answer:
JulsSmile [24]4 years ago
6 0
First you need to multiply all the numbers to get 11548845 and then for example you need to do this (77*1515)+(77*99)+(99*1515) = 274263 to get and then you need you need to add 77,1515,99 to get 1691 and then you add 11548845, 274263, and 1691 to get 11824799 and that is the total number of possible outcomes of meals that you can get.
<em> hope this helps you and the the reason I explained is so you dont have to ask this type of question again.</em>

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{ \boxed{\boxed{\begin{array}{cc} \maltese  \bf \: given \\  \\  \rm \: f(x) = ( {x}^{2}  + 16)( {x}^{2} - 9) \\  \\  \bf \: for \: zeroes \\  \\ \pink{ \boxed{\boxed{\begin{array}{c | c}   \bf \:  {x}^{2} + 16 = 0 & \bf \: {x}^{2}  - 9 = 0 \\  \\  =  >  {x}^{2}  =  - 16& {x}^{2}  = 9 \\  \\  =  > x =  \pm \sqrt{ - 16} &x =  \pm \:  \sqrt{9}  \\  \\  =  > x =  \pm \sqrt{ {i}^{2}  {4}^{2} } &x =  \pm \:  \sqrt{ {3}^{2} } \\  \\  =  > x =  \pm \: 4i&x =  \pm3  \end{array}}}}   \\  \\  \rm \: x =  \pm3 \: and \pm \: 4i\end{array}}}}

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