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NISA [10]
3 years ago
15

I need help i dont understand this,and j have and i have a big test coming up please help thanks

Mathematics
1 answer:
levacccp [35]3 years ago
7 0
Since both of the angles are supplementary, you'd set the expressions up into an equation equal to 180(degrees).
So, your equation should look like:
                       22x + 4 + 35x + 5 = 180.
Next, you combine your like terms so that your next move will look like:
                       57x + 9 = 180.
Then you'd follow the subtraction and division property, so your next moves will look as the following:
                       57x + 9 - 9 = 180 - 9 equals 171
                       57x / 57 = 171 / 57 equals 3
So, finally, your answer is: x = 3.
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Trapezoid EFGH has coordinates E(−3, 4) , F(1, 4), G(3, 1) , and H(−5, 1) . Trapezoid E'F'G'H' has coordinates E′(−12, 16) , F′(
julia-pushkina [17]
I believe that the answer would be C
8 0
3 years ago
Read 2 more answers
Which completely describes the polygon?
bogdanovich [222]

option D none of the above

4 0
2 years ago
I need helpppppppp!!!
yarga [219]

Answer: i would say probably 3 or -3

I hope it helps

3 0
3 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
2 years ago
How do I find the measurement of this ARC m&lt;IEF
andrey2020 [161]
The measure of a central angle is equal to measure of a minor arc. That makes m<GEH=17x+12. By the Vertical Angles Theorem, m<GEH and m<IEF are equal to each other (m<GEH=17x+12=m<IEF). By the same theorem, m<FEG and m<IEH are also equal (m<FEG=8x-7=m<IEH). The angles in a circle must all add up to 360 degrees, 2(17x+12)+2(8x-7)=360. Solve for x, then plug x into the equation for m<IEF.
Hope this helps!
4 0
3 years ago
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