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navik [9.2K]
3 years ago
10

PETS Becky wants to buy some fish for her aquarium. She has $20 to spend and the fish cost $2.50 each. Write and solve an inequa

lity to find how many fish Becky can afford.
Mathematics
1 answer:
Vilka [71]3 years ago
6 0
To start, you want to determine the inequality. You can do this by setting the number of buying n fish to be less than or equal to her current amount of money, being as it can't go over or she wouldn't be able to afford the fish. This inequality would be written so her amount of money (20) would be greater than or equal to the cost of n fish (2.5n), which would then look as such: 20≥2.5n. To solve this inequality, just solve for n by dividing both sides by 2.5, giving you 8≥n. This would mean that Becky can afford to buy up to 8 fish.
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Teacher raises A school system employs teachers at
Cerrena [4.2K]

By adding a constant value to every salary amount, the measures of

central tendency are increased by the amount, while the measures of

dispersion, remains the same

The correct responses are;

(a) <u>The shape of the data remains the same</u>

(b) <u>The mean and median are increased by $1,000</u>

(c) <u>The standard deviation and interquartile range remain the same</u>

Reasons:

The given parameters are;

Present teachers salary = Between $38,000 and $70,000

Amount of raise given to every teacher = $1,000

Required:

Effect of the raise on the following characteristics of the data

(a) Effect on the shape of distribution

The outline shape of the distribution will the same but higher by $1,000

(b) The mean of the data is given as follows;

\overline x = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i}

Therefore, following an increase of $1,000, we have;

 \overline x_{New} = \dfrac{\sum (f_i \cdot (x_i + 1000))}{\sum f_i} =  \dfrac{\sum (f_i \cdot x_i + f_i \cdot 1000))}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + \dfrac{\sum (f_i \cdot 1000)}{\sum f_i}

\overline x_{New} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + \dfrac{\sum (f_i \cdot 1000)}{\sum f_i} = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i} + 1000 = \overline x + 1000

  • Therefore, the new mean, is equal to the initial mean increased by 1,000

Median;

Given that all salaries, x_i, are increased by $1,000, the median salary, x_{med}, is also increased by $1,000

Therefore;

  • The correct response is that the median is increased by $1,000

(c) The standard deviation, σ, is given by \sigma =\sqrt{\dfrac{\sum \left (x_i-\overline x  \right )^{2} }{n}};

Where;

n = The number of teaches;

Given that, we have both a salary, x_i, and the mean, \overline x, increased by $1,000, we can write;

\sigma_{new} =\sqrt{\dfrac{\sum \left ((x_i + 1000) -(\overline x  + 1000)\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x  - 1000\right )^{2} }{n}}

\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x  - 1000\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}}

\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}} =\sqrt{\dfrac{\sum \left (x_i-\overline x  \right )^{2} }{n}} = \sigma

Therefore;

\sigma_{new} = \sigma; <u>The standard deviation stays the same</u>

Interquartile range;

The interquartile range, IQR = Q₃ - Q₁

New interquartile range, IQR_{new} = (Q₃ + 1000) - (Q₁ + 1000) = Q₃ - Q₁ = IQR

Therefore;

  • <u>The interquartile range stays the same</u>

Learn more here:

brainly.com/question/9995782

6 0
3 years ago
Find the area of the rectangle below
algol13
30 square cm that’s the answer
7 0
3 years ago
A length is measured at 21 cm correct to two significant figures, what is the lower bound of the length and upper bound?
Andreyy89

Answer:

20.5 and 21.5

Step-by-step explanation:

It says 2 significant figures so the least it can possibly be is 0.5 less and the most it can be is 0.5 more as if it was, lets say 20.4 it would round down to 20 not 21.

7 0
2 years ago
What are the last 2 digits of 7 to the power of 2018. This question was on a past exam paper.
Xelga [282]

Answer:

49

Step-by-step explanation:

  • Try finding pattern of last two digits of 7 to the power of some numbers.

7^1=07

7^2=49

7^3=343

7^4= 2301

7^5= 16807

  • so , the pattern is, 07,49,43,01
  • so, if we start writing all numbers from 1 to 2018 , four number in each line, 2018 will fall in the second column.
  • so it will have 49 as the  last 2 digits [by seeing this pattern : 07,49,43,01 ]
6 0
3 years ago
With a beginning balance of $2500 and no additional charges, there is no grace-period, you will just pay the minimum payment eac
valkas [14]

Answer:

a = $31.23 per month

b = $20.83 per month

c = 249.98 = $249.98 interest charges

                   = $624-249.98 = 374.02 profit part decrease 8% inc.                  

d = 35.35%

e = Answer is in the name; basic payment is a contract which means whilst account remains open charges are requested without fail. Should balance be less or on zero, charges are still applied.

Step-by-step explanation:

2500 x 1.2499 = interest only for start month 13 =3124.75

3124.75/ 100 x 1.08   = 8% of this = 249.98 each year.

We only have to divide each by 12 to work out monthly individual charges and subtract to find out payments.

3124.75 - 249.98 = 2874.77 = Total after charges each year.

249.98/12 = 20.83 = monthly charges.

3124.75- 2500 = 624.75 payments each year

624.75/12 = 52.06 month 1 payment before charge

52.06-20.83 =31.23 total minimum payment

2500 + 249.98

Percentage = 200:600 = 1/3 33% + (comparing to ratio 10:25 closer to 40%)

We find ratio 200:600= 33.33 + 49.995/24.75 = 2.02

33+2.02 = 35.35%

7 0
3 years ago
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