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lutik1710 [3]
3 years ago
6

Write a method named showChar. The method should accept two arguments: a reference to a String object and an integer. The intege

r argument is a character position within the String, with the first character being at position 0. When the method executes, it should display the character at that character position. The method does not return anything. Here is an example of a call to the method: showChar("New York", 2); In this call, the method will display the character w because it is in position 2. Demonstrate the method in a complete program. Sample Run java Method_showChar Enter a line of text: The elevation of Mount Everest is 29,029 feet (8,848·in·meters)↵ Enter yourindex:3 5↵ 9↵
Computers and Technology
1 answer:
matrenka [14]3 years ago
5 0

A complete program with the method ShowCar:

import java.util.Scanner; // header file

public class ShowChar

{

public static void main(String[] args)

{

String lnOfText;

int i;

Scanner input = new Scanner(System.in);

System.out.print("Enter a line of text:");

lnOfText = input.nextLine();

System.out.print(" Enter your index: ");

i = input.nextInt();

show_Char(lnOfText,i);

}

public static void show_Char(String str_a, int i)

{

System.out.print(str_a.charAt(i));

}

}

In this program, both the inputs ie. a sentence or line of text as well as the index position is obtained. A method is written to find the string at that particular position. Finally the method prints that character at the particular index.

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Assume you are given a boolean variable named isNegative and a 2-dimensional array of ints that has been created and assigned to
Anon25 [30]

Answer:

#include <iostream>

using namespace std;

int main(){

   int rows, cols;

   bool isNegatives;

   cout<<"Rows: ";

   cin>>rows;

   cout<<"Columns: ";

   cin>>cols;

   int a2d[rows][cols];

   for(int i =0;i<rows;i++){

   for(int j =0;j<cols;j++){

       cin>>a2d[i][j];}    }

   int negatives, others = 0;

   for(int i =0;i<rows;i++){

   for(int j =0;j<cols;j++){

       if(a2d[i][j]<0){

           negatives++;}

       else{

           others++;}}    }

   if(negatives>others){

       isNegatives = true;}

   else{

       isNegatives = false;}

   cout<<isNegatives;  

   return 0;

}

Explanation:

For clarity and better understanding of the question, I answered the question from the scratch.

This line declares number of rows and columns

   int rows, cols;

This line declares the Boolean variable

   bool isNegatives;

This line prompts user for rows

   cout<<"Rows: ";

This line gets the number of rows

   cin>>rows;

This line prompts user for columns

   cout<<"Columns: ";

This line gets the number of columns

   cin>>cols;

This line declares the array

   int a2d[rows][cols];

This line gets user input for the array

<em>    for(int i =0;i<rows;i++){</em>

<em>    for(int j =0;j<cols;j++){</em>

<em>        cin>>a2d[i][j];}    }</em>

This line declares and initializes number of negative and others to 0

   int negatives, others = 0;

The following iteration counts the number of negatives and also count the number of non negative (i.e. others)

<em>    for(int i =0;i<rows;i++){</em>

<em>    for(int j =0;j<cols;j++){</em>

<em>        if(a2d[i][j]<0){</em>

<em>            negatives++;}</em>

<em>        else{</em>

<em>            others++;}}    }</em>

This checks of number of negatives is greater than others

   if(negatives>others){

If yes, it assigns true to isNegatives

       isNegatives = true;}

   else{

If otherwise, it assigns false to isNegatives

       isNegatives = false;}

This prints the value of isNegatives

   cout<<isNegatives;  

<em>See attachment</em>

Download cpp
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