Answer:
The stone will be in flight for 3 seconds
Step-by-step explanation:
Given the equation;
d = -16t^2 + vt + h
Where;
v = the initial velocity
h = the initial height
Given;
v = 48 ft/s
h = 0
Substituting into function d;
d = -16t^2 + 48t + 0
d = -16t^2 + 48t
At the point of launch and the point of landing d = 0.
We need to calculate the values of t for d to be equal to zero.
d = -16t^2 + 48t = 0
-16t^2 + 48t = 0
Factorising, we have;
16(-t+3)t = 0
So,
t = 0 or -t+3 = 0
t= 0 or t =3
Change in t is;
∆t = t2 - t1 = 3 - 0
∆t = 3 seconds.
The stone will be in flight for 3 seconds.
Y-(-8)=-0.24(x-3)
y+8=-0.24(x-3)
Answer:
18
Step-by-step explanation:
6(7e+3)=6*7e + 6*3=42e + 18
Answer:
2.25 miles of road they have to build this week
Step-by-step explanation:
Given:
Total distance of the road = 3 miles
Distance constructed on Tuesday = 1/4 mile of road.
To Find:
Miles of road still have to be built this week=?
Solution:
Let the Distance that have to be built be X
Then,
X= total distance of the Road – the distance built on Tuesday
X = 3 –
X = 3 -
X =
X=
X= 2.25 miles