Check the schedule and do the jobs as they relate to the schedule
<u>Answer:</u>
First mechanic worked for 20 hours and second mechanic worked for 15 hours.
<u>Solution:</u>
Given, Two mechanics worked on a car.
The first mechanic charged $45 per hour, and the second mechanic charged $120 per hour.
The mechanics worked for a combined total of 35 hours, and together they charged a total of $2700.
We have to find how long did each mechanic work.
Let the time worked by 1st mechanic be t hours then time taken by 2nd mechanic will be 35 – t hours.
Now, according to given information,
45 x t + 120
(35 – t) = 2700
45t + 120
35 – 120t = 2700
-75t + 4200 = 2700
75t = 4200 – 2700
75t = 1500
t = 20
hence, 1st mechanic worked for 20 hours and 2nd mechanic worked for 35 – 20 = 15 hours.
2/a= a/50
Cross multiply:
a* a= 2*50
⇒ a^2= 100
⇒ a= √100 or a= -√100
⇒ a= 10 or a= -10
Final answer: a= 10 or a= -10~
The place value of the 5 is 10 times the place value of the 9 in 159.20. The 9 is in the units position.
Answer:
Step-by-step explanation:
Directions: Write an integer to model each situation.
(1) a $60 withdrawal
(2) 7 strokes below par
(3) a $180 profit
(4) laying off 20 workers
(5) a 4-yard loss
(6) a delivery fee
(7) ascending 800 feet
(8) draining 6 inches from a fish tank
(9) an elevation of 200 feet