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Keith paid 8.44 each for 5 lizard toys and got 5 cages for 8.45 each with 5 20 bills . How much change did Keith recive

Olegator [25]

Answer:

19.51

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which length measurement is the most precise.

vampirchik [111]

B: 6.03 The more numbers to the right of the decimal the more precise and accurate the number will be

5 0

3 years ago

Assume that the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. If th

ioda

Answer:

The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 69.0 inches and a standard deviation of 2.8 inches.

This means that $\mu = 69, \sigma = 2.8$

What is the bottom cutoff heights to be eligible for this experiment?

The bottom 15% are excluded, so the bottom cutoff is the 15th percentile, which is X when Z has a pvalue of 0.15. So X when Z = -1.037.

$Z = \frac{X - \mu}{\sigma}$

$-1.037 = \frac{X - 69}{2.8}$

$X - 69 = -1.037*2.8$

$X = 66.1$

The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

8 0

3 years ago

A poster is to have a total area of

Neko [114]

Answer:

Dimensions of printed area

w = 8.95 cm

h = 13.44 cm

A(max) = 120.28 cm²

Step-by-step explanation:

Lets call " x " and "y" dimensions of the poster area ( wide and height respectively) . Then

A(t) = 180 cm² = x*y y = 180/ x

And the dimensions of printed area is

A(p) = ( x - 2 ) * ( y - 3 ) then as y = 180/x we make A function of x only so

A(x) = ( x - 2 ) * ( 180/x - 3 ) ⇒ A(x) = 180 - 3x - 360/x +6

A(x) = - 3x - 360 /x + 186

Taking derivatives on both sides of the equation we get:

A´(x) = -3 + 360/ x²

A´(x) = 0 -3 + 360/ x² = 0 -3x² + 360 = 0

x² = 120 ⇒ x = √120 x = 10.95 cm

And y = 180 / 10.95 ⇒ y = 16.44 cm

Then x and y are the dimensions of the poster then according to problem statement

w of printed area is x - 2 = 10.95 - 2 = 8.95 cm

and h of printed area is y - 3 = 16.44 - 3 = 13.44 cm

And the largest printed area is w * h = ( 8.95)*(13.44)

A(max) = 120.28 cm²

7 0

3 years ago

Identify the slope that goes through the two given coordinate points, -3,0 and 3,2. A. -3

nirvana33 [79]

1) with the the following equation you can find the slope having two points

m = Y2-Y1/X2-X1 , A(-3,0) B(3,2)

m= 2-(0) / 3-(-3) m = 2/6 = 1/3, the correct option is C

5 0

3 years ago