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o-na [289]
3 years ago
11

The ratio of dogs to cats 2 to 5. If there are 20 cats, how many dogs are there?

Mathematics
2 answers:
Rzqust [24]3 years ago
7 0

Answer:

50

Step-by-step explanation:

AlekseyPX3 years ago
4 0

2 * 10 = 20

5 * 10 = 50

therefore there are 50 dogs

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We know all these angles combined equals 360, so:

3x + 20 + 3x + 20 + x + x = 360
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x = 40

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Ravi is driving 440 miles to visit his grandma.
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You would use the formula: Rate = distance / time which equals 55

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55 = (3/4)(440) / t

t = 6 hours

So the answer would be "C"



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Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that
Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is P(x_1 + x_2 \ge 2 )= 0.5940

Step-by-step explanation:

From the question we are told that

     The rate at which fire breaks out every 10 years is  \lambda  =  1

  Generally the probability distribution function for Poisson distribution is mathematically represented as

               P(x) =  \frac{\lambda^x}{ k! } * e^{-\lambda}

Here x represent the number of state which is  2 i.e x_1 \ \ and \ \ x_2

Generally  the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

          P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 + x_2 \le 1 )

=>        P(x_1 + x_2 \ge 2 ) =  1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]

=>        P(x_1 + x_2 \ge 2 ) =  1 - [ P(x_1  = 0 ,  x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]

=>  P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)

=>    P(x_1 + x_2 \ge 2 ) =  1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}

=>   P(x_1 + x_2 \ge 2 )= 1- [[0.3678  * 0.3679] + [0.3678  * 0.3679] + [0.3678  * 0.3679]  ]

P(x_1 + x_2 \ge 2 )= 0.5940

               

3 0
3 years ago
Triangle ABC has vertices at A(−3, 4), B(4, −2), C(8, 3). The triangle translates 2 units up and 1 unit right. Which rule repres
Nataly [62]

Answer:

The translation statement is given by:

(x,y)\rightarrow (x+1,y+2)

After the translation, the coordinates of vertex A is (-2,6).

Step-by-step explanation:

Given :

Vertices of a triangle ABC are:

A(−3, 4), B(4, −2), C(8, 3)

The triangle is translated 2 units up and 1 unit right.

To find the co-ordinates of point A after translation.

Translation rules.

For shift of c units up, the translation is given as:

(x,y)\rightarrow (x,y+c)

For shift of k units right, the translation is given as:

(x,y)\rightarrow (x+k,y)

So, it says the triangles is translated 2 units up and 1 unit right.

The translation statement is given by:

(x,y)\rightarrow (x+1,y+2)

So, co-ordinates of point A after translation is given by :

(-3,4)\rightarrow (-3+1,4+2)=(-2,6)

After the translation, the coordinates of vertex A is (-2,6).

4 0
3 years ago
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