1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
d1i1m1o1n [39]
3 years ago
8

No? 6+6 solve it 8-7+x

Mathematics
2 answers:
jeka943 years ago
8 0

Answer:

X + 1

Step-by-step explanation:

Slav-nsk [51]3 years ago
3 0

Answer:

6+6=12 and x= -1

Step-by-step explanation:

8-7+x=0

1+x=0

x= -1

You might be interested in
I need help wit dis plz
Valentin [98]

Answer:

Bottom left

Step-by-step explanation:

It does not make a straight line

6 0
2 years ago
Ms. johnson's class is having a pizza party. if there are 14 students and 7 pizzas cut into 8 slices, what answer choice represe
Lubov Fominskaja [6]

We are asked about the fraction of pizza each student gets, so the relevant numbers here is only 14 students and 7 pizzas. SO the fraction of pizza each student get is the ratio of the two:

fraction = 7 pizzas / 14 students

fraction = 1 / 2

 

<span>So each student gets 1/2</span>

8 0
3 years ago
The fish tank has side lengths 20in, 10in and height 15in. The water level is two inches below the top of the tank. A glass sphe
Kitty [74]

Answer:

Part 1) The new distance from the water to the top of the tank is 1.979\ in

Part 2) The maximum number of balls that can be put into the tank with the tank not overflowing is 95

Step-by-step explanation:

step 1

Find the total volume of the tank

V=20*10*15=3,000\ in^{3}

step 2

Find the volume of the tank if the water level is two inches below the top of the tank

V=20*10*(15-2)=2,600\ in^{3}

step 3

Find the volume of the glass sphere

The volume of the glass sphere is equal to

V=\frac{4}{3}\pi r^{3}

we have

r=1\ in

assume

\pi=3.14

substitute

V=\frac{4}{3}(3.14)(1)^{3}

V=4.2\ in^{3}

step 4

What is the new distance from the water to the top of the tank?

we know that

2 in -----> represent (3,000-2,600)=400\ in^{3}

so

using proportion

Find how many inches correspond a volume of 4.2\ in^{3}

\frac{2}{400}\frac{in}{in^{3}}=\frac{x}{4.2}\frac{in}{in^{3}}\\ \\x=4.2*2/400\\ \\x=0.021\ in

The new distance from the water to the top of the tank is

2-0.021=1.979\ in

step 5

Find how many of these balls can be put into the tank with the tank not overflowing

we know that

The volume of one ball is equal to  4.2\ in^{3}

using proportion

\frac{1}{4.2}=\frac{x}{400}\\ \\x=400/4.2\\ \\x=95.23\ balls

therefore

The maximum number of balls that can be put into the tank with the tank not overflowing is 95

4 0
3 years ago
5x + 14 = K solve for K
siniylev [52]
 Flip the equation.<span>k=<span><span>5x</span>+<span>14</span></span></span>
3 0
3 years ago
Read 2 more answers
What is 9^21 can somebody please help me
stiv31 [10]
It is 9*9 21 times so 
9*9*9*9*9*9*9*9*9*9*9*9*9*9*9*9*9*9*9*9*9=

1.09418989e20 is the answer.

5 0
3 years ago
Read 2 more answers
Other questions:
  • Fifty-six biscuits are to be fed to 10 pets; each pet is either a cat or a dog. each dog is to get six biscuits, and each cat is
    7·1 answer
  • How many of the positive integer factors of 15552 are perfect squares?
    12·2 answers
  • A line that contains the point (2,-3) and has a slope of 8
    12·2 answers
  • The time required to complete a project is normally distributed with a mean of 80 weeks and a standard deviation of 10 weeks. Th
    13·1 answer
  • Identify the slope and y-intercept of the following line: 2y + 4 =-6x
    7·1 answer
  • Subject : Pythagorean Theorem
    10·1 answer
  • Find the new number given the Original number and the percent of change
    14·2 answers
  • 1
    6·1 answer
  • Question<br> Find the value of x.<br><br><br><br> x=
    5·1 answer
  • At a swim meet, 8 different swimmers compete in the 800- meter freestyle race. How many different ways are there for these swimm
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!