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poizon [28]
3 years ago
8

Calculate the partial pressure of the CO2 in the expired air at its peak, assuming 1 atm pressure and a body temperature of 37∘C

.
Chemistry
1 answer:
kvasek [131]3 years ago
4 0

Answer:

P2= 45.50 atm

Explanation:

If the amount of gas in the tanks remains same we use the equation P1T1=P2T2

40 x 281.15 = P2 x 247.15

P2= 45.50 atm

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4 0
3 years ago
HELP ASAP!!!
Paraphin [41]
Solution..
---------------

Let's calculate the mass of CO₂.

We have (12+(16*2))
= 12+32
=44gmol¯¹..

a. What is the percent by mass of carbon?

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12/44 × 100%

=27.3%...

b. What is the percent by mass of oxygen?

Mass of oxygen/mass of CO₂ × 100%

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Hope this helped....?
8 0
3 years ago
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A gas system has volume, moles and temperature of 9040 mL, 0.447 moles and -35.50 oC, respectively. What is the pressure in atm?
babymother [125]

Answer : The pressure of the gas is, 0.964 atm

Solution : Given,

Volume of gas = 9040 ml = 9.040 L        (1 L = 1000 ml)

Moles of gas = 0.447 moles

Temperature of gas = -35.50^oC=237.5K       (0^oC=273K)

Using ideal gas equation,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = gas constant = 0.0821Latm/moleK

Now put all the given values in this formula, we get the pressure of the gas.

P(9.040L)=(0.447moles)\times (0.0821Latm/moleK)\times (237.5K)

By rearranging the terms, we get

P=0.964atm

Therefore, the pressure of the gas is, 0.964 atm

7 0
2 years ago
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