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3 years ago

you have two samples of gray powder both which are flammable these are powders the same substance explain why

Chemistry

2 answers:

nasty-shy [4]3 years ago

7 0

The amount of matter stays the same between the substances,

Jet001 [13]3 years ago

5 0

Answer:it help in gravity

Explanation:

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What happens to the melting points of these metals

statuscvo [17]

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3 years ago

I'll mark brainly pls help

Marta_Voda [28]

I feel bad that nobody answered

4 0

3 years ago

Why does it matter if atoms are divisible ???

Andreyy89

Atoms are divisible contrary to the early beliefs that the smallest "indivisible" matter is an atom. When an atom loses its identity it means that they are divisible. Atoms chemically react with other kinds of atoms thus changing their activity.

They certainly are not that important to our lives, but it’s good to know :)

5 0

3 years ago

1. The pressure of a gas is 100.0 kPa and its volume is 500.0 ml. If the volume increases to 1,000.0 ml, what is the new pressur

marta [7]

Answer:

1) The new pressure of the gas is 500 kilopascals.

2) The final volume is 1.44 liters.

3) Volume will decrease by approximately 67 %.

4) The Boyle's Laws deals with pressures and volumes.

Explanation:

1) From the Equation of State for Ideal Gases we construct the following relationship:

$\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}$ (1)

Where:

$P_{1}, P_{2}$ - Initial and final pressure, measured in kPa.

$V_{1}, V_{2}$ - Initial and final pressure, measured in mililiters.

If we know that $P_{1} = 100\,kPa$ , $V_{1} = 500\,mL$ and $V_{2} = 1000\,mL$ , then the new pressure of the gas is:

$P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)$

$P_{2} = 500\,kPa$

The new pressure of the gas is 500 kilopascals.

2) Let suppose that gas experiments an isothermal process. From the Equation of State for Ideal Gases we construct the following relationship:

$\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}$ (1)

Where:

$P_{1}, P_{2}$ - Initial and final pressure, measured in kPa.

$V_{1}, V_{2}$ - Initial and final pressure, measured in mililiters.

If we know that $V_{1} = 3.60\,L$ , $P_{1} = 10\,kPa$ and $P_{2} = 25\,kPa$ then the new volume of the gas is:

$V_{2} = V_{1}\cdot \left(\frac{P_{1}}{P_{2}} \right)$

$V_{2} = 1.44\,L$

The final volume is 1.44 liters.

3) From the Equation of State for Ideal Gases we construct the following relationship:

$\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}$ (1)

Where:

$P_{1}, P_{2}$ - Initial and final pressure, measured in kPa.

$V_{1}, V_{2}$ - Initial and final pressure, measured in mililiters.

If we know that $\frac{P_{2}}{P_{1}} = 3$ , then the volume ratio is:

$\frac{V_{1}}{V_{2}} = 3$

$\frac{V_{2}}{V_{1}} = \frac{1}{3}$

Volume will decrease by approximately 67 %.

4) The Boyle's Laws deals with pressures and volumes.

8 0

3 years ago

A hot pack contains chemicals that can be activated to produce heat. A cold pack contains chemicals that feel cold when activate

boyakko [2]

Answer:

Explanation is given below.

Explanation:

The cold pack is applied on the injured part of body only the place where the type of injury is Sprain, swelling, or any other internal small injury. This is applied to lower the flow of blood in that particular area which reduces the further inflammation of that area.

For the applied pack the direction of the flow of the heat will be towards the cold pack which will absorb the heat of the injured part as the heat always flows from higher temperature to the lower temperature.

This method of treatment of an injury is the instant way of treating an injury which prevents further problem to the injury by reducing the blood flow to the site and cooling the affected area.

4 0

4 years ago

you have two samples of gray powder both which are flammable these are powders the same substance explain why ​

you have two samples of gray powder both which are flammable these are powders the same substance explain why