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3 years ago

If an element forms 1- ion, in which group of the periodic table would you expect to find it

Chemistry

2 answers:

elena55 [62]3 years ago

7 0

Answer:

the correct answer is 17

irina1246 [14]3 years ago

4 0

Many of the elements on the periodic table will always form ions that have the same charge. The alkali metals (shown in yellow) always form +1 ions. The alkaline earth metals (red) always form +2 ions. The halogens (blue) always form -1 ions.

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2.50 g of Zn is added to 5.00 g of HCl

Debora [2.8K]

Zn+2HCl ----> 2ZnCl2 + H2

For 2.50 g of Zn

Mass per mol = 2.50/molar mass of Zn = 2.50/65.38 = 0.0382 g/mol
There are two moles of ZnCl2 and total mass = 2*0.0382*molar mass of ZnCl2 = 2*0.0382*136.286 = 10.42 g

For 2 g of HCl

Mass per mol = 2/2*molar mass of HCl = 2/ (2*36.46) = 0.0274 g/mol
For the two moles of ZnCl2, mass produced = 2*0.0274*136.286 = 7.48 g

It can be noted that 2 g of HCl produced less amount of ZnCl and thus it is the limiting reagent.

5 0

3 years ago

How many molecules are in 3.6 grams of NaCl?

raketka [301]

Answer:

$\boxed{\text{None}}$

Explanation:

There are no molecules in NaCl, because it consists only of ions.

However, we can calculate the number of formula units (FU) of NaCl.

Step 1. Calculate the moles of NaCl

$\text{No. of moles}=\text{3.6 g NaCl}\times \dfrac{\text{1 mol NaCl}}{\text{63.54 g NaCl}} = \text{0.0567 mol NaCl}$

Step 2. Convert moles to formula units

$\text{FU} = \text{0.0567 mol NaCl} \times \dfrac{6.022 \times 10^{23}\text{ FU NaCl}}{\text{1 mol NaCl}}\\\\= 3.4 \times 10^{22} \text{ FU NaCl}$

There are $\boxed{3.4 \times 10^{22} \text{ FU NaCl}}$ in 3.6 g of NaCl.

6 0

3 years ago

Mole are in 5.1 grams of beryllium ?

chubhunter [2.5K]

5.1/9.01 ≈ 0.566 moles

7 0

3 years ago

The average atomic weight of copper, which has two naturally occurring isotopes, is 63.5. One of the isotopes has an atomic weig

Darya [45]

<u>Answer:</u> The atomic weight of the second isotope is 64.81 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of atomic masses of each isotope each multiplied by their natural fractional abundance

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

We are given:

Let the mass of isotope 2 be 'x'

Mass of isotope 1 = 62.9 amu

Percentage abundance of isotope 1 = 69.1 %

Fractional abundance of isotope 1 = 0.691

Mass of isotope 2 = 'x'

Percentage abundance of isotope 2 = 30.9%

Fractional abundance of isotope 2 = 0.309

Average atomic mass of copper = 63.5 amu

Putting values in equation 1, we get:

$\text{Average atomic mass of copper}=[(62.9\times 0.691)+(x\times 0.309)]$

$x=64.81amu$

Hence, the atomic weight of second isotope will be 64.81 amu.

4 0

3 years ago

A 5.0 L flask contains 0.60 g of 02 at a temperature of 22*C, what is the pressure inside the flask?

Kruka [31]

Answer:

The pressure inside the flask is 0,09 atm

Explanation:

We calculate the number of moles of O2, we convert the Temperature into unit KELVIN and use the formula of the ideal gases to calculate the pressure:

Weight 1 mol of 02= 15,999g x2= 32g

32g---1mol 02

0,60g---x=(0,60gx1mol O2)/32g= 0,019mol O2

T(K)=273+22=295K

PV=nRT

Px5.0l= 0,019mol x 0,082 lxatm/Kxmolx295 K

P=(0,019mol x 0,082 lxatm/Kxmolx295 K)/5.0l

P=0,09atm

4 0

3 years ago