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3 years ago

If an element forms 1- ion, in which group of the periodic table would you expect to find it

Chemistry

2 answers:

elena55 [62]3 years ago

7 0

Answer:

the correct answer is 17

irina1246 [14]3 years ago

4 0

Many of the elements on the periodic table will always form ions that have the same charge. The alkali metals (shown in yellow) always form +1 ions. The alkaline earth metals (red) always form +2 ions. The halogens (blue) always form -1 ions.

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When preparing for work in the fume hood, be sure to gather all necessary tools, glassware, and chemicals _________ to minimize

andreyandreev [35.5K]

Answer:

In advance

middle

lower

Explanation:

These are the safety precautions needed when carrying out duties in the fume hood.

When planning and preparing to work in a fume hood (a locally designed area to reduce exposure to hazardous fumes). It is advisable to make all equipment readily available at your disposal in advance to reduce and minimize the raising and lowering of the hood sash at intervals.

It is also pertinent to understand that working in the middle of the work surface helps to promote the movement of air and keeps the area neat and tidy.

However, if any case where there is a need to get a new tool or equipment during the process of working in a fume hood, it is advisable to lower the sash at that point in time.

5 0

3 years ago

1.20 x 10^22 molecules NaOH to gram

Trava [24]

Answer:

$\boxed {\boxed {\sf 0.797 \ g \ NaOH}}$

Explanation:

1. Convert Molecules to Moles

First, we must convert molecules to moles using Avogadro's Number: 6.022*10²³. This tells us the number of particles in 1 mole of a substance. In this case, the particles are molecules of sodium hydroxide.

$\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}$

Multiply by the given number of molecules.

$1.20*10^{22} \ molecules \ NaOH *\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}$

Flip the fraction so the molecules cancel out.

$1.20*10^{22} \ molecules \ NaOH *\frac {1 \ mol \ NaOH} {6.022*10^{23} \ molecules \ NaOH}}$

$1.20*10^{22} *\frac {1 \ mol \ NaOH} {6.022*10^{23}}}$

$\frac {1.20*10^{22} \ mol \ NaOH} {6.022*10^{23}}}$

$0.0199269345732 \ mol \ NaOH$

2. Convert Moles to Grams

Next, we convert moles to grams using the molar mass.

We must calculate the molar mass using the values on the Periodic Table. Look up each individual element.

Na: 22.9897693 g/mol
O: 15.999 g/mol
H: 1.008 g/mol

Since the formula has no subscripts, we can simply add the molar masses.

NaOH: 22.9897693+15.999+1.008=39.9967693 g/mol

Use this as a ratio.

$\frac {39.9967693 \ g \ NaOH }{1 \ mol \ NaOH}$

Multiply by the number of moles we calculated.

$0.0199269345732 \ mol \ NaOH*\frac {39.9967693 \ g \ NaOH }{1 \ mol \ NaOH}$

The moles of sodium hydroxide cancel.

$0.0199269345732 *\frac {39.9967693 \ g \ NaOH }{1}$

$0.0199269345732 *39.9967693 \ g \ NaOH$

$0.79701300498 \ g \ NaOH$

The original measurement of molecules has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 0 tells us to leave the 7 in the hundredth place.

$0.797 \ g \ NaOH$

1.20*10²² molecules of sodium hydroxide is approximately 0.797 grams.

4 0

3 years ago

The bond between F and Cl would be: pure covalent polar covalent ionic metallic

shusha [124]

Answer:

Polar Covalent

Explanation:

Chlorine and Fluorine are both halogens. They are in group VII.

The Pauling's electronegativity value of these elements are:

F = 4.0

Cl = 3.0

Electronegativity of an element is a property that combines the ability of its atom to lose and gain electrons. It can be used to predict bond type.

For heteronuclear molecules where the electronegativity difference is between 0.5 and 1.7 there will not be an equal sharing of the electron pair between the atoms involved.

The bond that results is a Polar Covalent bond.

When the electronegativity difference is zero or less than 0.5, a non-polar covalent bond forms. There would be an equal sharing of the electron pair donated.

3 0

4 years ago

Please answer

timofeeve [1]

Answer:

1) petroleum, mixture, not found on periodic table

2) hydrogen and helium, mixture, contains "and"

3) iron sulphide, compound, ends with "ide"

4) carbon dioxide, compound, ends with "ide"

5) salt water, mixture, not found on periodic table

6) milk and sugar, mixture, contains "and"

7) silver nitrate, compound, ends with "ate"

8) sodium carbonate, compound, ends with "ate"

9) carbon electrode, mixture, not found on periodic table

10) astatine, element, found on periodic table

11) argon, element, found on periodic table

12) oxidane, compound, contains "ane"

13) iron and sulphur, mixture, contains "and"

14) methane, compound, contains "ane"

Explanation:

5 0

3 years ago

What happens to an elements property when he doesnt pay his taxes?

Karolina [17]

Answer:

I've got a feeling...

Explanation:

What?

4 0

3 years ago