It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
Answer:
1)
2)
3)
And the variance would be given by:
And the deviation would be:
4)
And the variance would be given by:
And the deviation would be:
Step-by-step explanation:
For this case we have the following distributions given:
Probability M J
0.3 14% 22%
0.4 10% 4%
0.3 19% 12%
Part 1
The expected value is given by this formula:
And replacing we got:
Part 2
Part 3
We can calculate the second moment first with the following formula:
And the variance would be given by:
And the deviation would be:
Part 4
We can calculate the second moment first with the following formula:
And the variance would be given by:
And the deviation would be:
Answer:
The distance should be
Step-by-step explanation:
Distance formula