The final stabilized temperature will be between 0 °C and 50 °C.
<h3>
Calorimetry:</h3>
The enthalpy of fusion of ice is 334 J/g. The specific heat of water is 4.2 J/g.
To cool 100 g of water from 100 °C to 0 °C would require the removal of
4.2 x 100 x 100 = 42000 J.
To melt the ice would require the addition of
334 x 100 = 33400 J
∴ 42000 > 33400 thus you can melt all the ice and have some heat to spare, specifically 42000 - 33400 = 8600 J
Now use this to warm up 100+100 = 200 g of water at 0 °C
The final stabilized temperature;
8600 / (200 x 4.2) = 10.23 °C
Therefore, the final stabilized temperature is 10.23 °C
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Answer:
The image to the left (with the disks on it)
Explanation:
Interference in any type of wave can be gotten in two forms, constructive interference, and destructive interference.
The constructive interference is between two waves with the same phase, that is, each crest and trough correspond with the crest and trough of the another getting as result a wave with twice the amplitude of the original one.
The destructive interference is between two waves out of phase, in which the crest of one cancels with the trough of another.
If light passes for a slit it will get a diffraction pattern in a screen, at which each bright pattern corresponds to a crest and a dark pattern to a trough, as a consequence of constructive interference and destructive interference in different points of its propagation to the screen.
The circular shape of the disks can be a representation of the wavefront and how the overlaps make constructive and destructive interference in order to get the diffraction pattern.
Velocity - v =0 m/s,
initial velocity - v(0)= 40 m/s
a - acceleration,
time - t = 12 s.
v=v(0) - at
0 = 40m/s - a*12s
12a = 40
a = 3.3 m/s²
Answer:
A. the magnitude of the force between the spheres is 3.97 x 10⁻⁴ N
B. the magnitude of its initial acceleration is 5.83 m/s²
Explanation:
given information:
metal sphere's mass, m = 0.1 g = 1 x 10⁻⁴ kg
charge, q = -21 nC = -2.1 x 10⁻⁸
r = 10 cm = 0.1 m
What is the magnitude of the force between the spheres?
F₁₂ = k q₁q₂/r²
= ( 9 x 10⁹) (-2.1 x 10⁻⁸)²/(0.1)²
= 3.97 x 10⁻⁴ N
If the upper sphere is released, it will begin to fall. What is the magnitude of its initial acceleration?
mg - F₁₂ = ma
a = g - (F₁₂/m)
= 9.8 - (3.97 x 10⁻⁴/1 x 10⁻⁴)
= 5.83 m/s²
