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nikklg [1K]
4 years ago
15

Which picture best demonstrates the phenomenon of diffraction?

Physics
1 answer:
timama [110]4 years ago
5 0

Answer:

The image to the left (with the disks on it)

Explanation:

Interference in any type of wave can be gotten in two forms, constructive interference, and destructive interference.

The constructive interference is between two waves with the same phase, that is, each crest and trough correspond with the crest and trough of the another getting as result a wave with twice the amplitude of the original one.

The destructive interference is between two waves out of phase, in which the crest of one cancels with the trough of another.

If light passes for a slit it will get a diffraction pattern in a screen, at which each bright pattern corresponds to a crest and a dark pattern to a trough, as a consequence of constructive interference and destructive interference in different points of its propagation to the screen.

The circular shape of the disks can be a representation of the wavefront and how the overlaps make constructive and destructive interference in order to get the diffraction pattern.

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Agata [3.3K]
78 nitrogen I think
4 0
3 years ago
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A single conservative force F = (7.0x - 11) N, where x is in meters, acts on a particle moving along an x axis. The potential en
Umnica [9.8K]

Answer:

(a) 34.6429J

(b) -1.57 m

(c) 4.71 m

Explanation:

The derivative of the potential energy with respect to the position is equal to the negative of the force, so:

-\frac{dU}{dx}=F\\ dU=-Fdx

Then, if we integer both sides, we get:

∫dU = -∫(7x - 11)dx

U=\frac{-7}{2}x^{2} + 11x + c

we know that U is equal to 26 J when x is zero, so:

U=\frac{-7}{2}x^{2} + 11x + c

26=\frac{-7}{2}(0)^{2} + 11(0) + c

26=c

Finally, the equation for the potential energy is:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

Therefore, the maximum positive potential energy is the energy when x is equal to 11/7. That is because the equation of U is the equation of a parable, and the vertex in a parable is given by:

x=\frac{-b}{2a} = \frac{-11}{2(-7/2)} =\frac{11}{7}

Where b is the number beside x and a is the number beside x^{2}, Then, the value of maximum U is:

U(11/7)=\frac{-7}{2}(11/7)^{2} + 11(11/7) + 26

U(11/7)=34.6429J

On the other hand, the negative and positive values of x where the potential energy is equal to zero is calculated as:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

0=\frac{-7}{2}x^{2} + 11x + 26

if we solve this using the quadratic equation, we get:

x =\frac{-11+\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=-1.5747

x =\frac{-11-\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=4.7175

Finally, the negative and positive values of x where the potential energy is equal to zero are -1.5747 and 4.7175 respectively.

3 0
3 years ago
What is the acceleration of an object that takes 20 sec to change from a speed of 200 m/s to 300 m/s ?
marin [14]

<u>Given</u><u>:</u>

  • initial velocity, u = 200 m/s

  • Final velocity, v = 300 m/s

  • Time taken, t = 20 sec

<u>To</u><u> </u><u>be</u><u> </u><u>calculated</u><u>:</u>

Calculate the acceleration of given object ?

<u>Formula</u><u> </u><u>used</u><u>:</u>

Acceleration = v - u / t

<u>Solution</u><u>:</u>

We know that,

Acceleration = v - u / t

☆ Substituting the values in the above formula,we get

Acceleration ⇒ 300 - 200 / 20

⇒ 100/20

⇒ 5 m/s²

5 0
4 years ago
I NEED HELP PLEASE, THANKS! :)
Neko [114]

Answer:

Take a look at the attachment below.

Explanation:

4 0
4 years ago
What about an atom can we learn by studying the bohr model?
zubka84 [21]

Answer:

The Bohr model shows that the electrons in atoms are in orbits of differing energy around the nucleus

Explanation:

(think of planets orbiting around the sun). Bohr used the term energy levels (or shells) to describe these orbits of differing energy.

8 0
2 years ago
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