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3 years ago

What two whole numbers will the v54 fall between?

Mathematics

1 answer:

blsea [12.9K]3 years ago

3 0

Answer:

7 and 8

Step-by-step explanation:

7 X 7= 49 8 X 8= 64 and you can't get closer unless you make it a decimal

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5/12-3/8 In Simplest form can someone please break it down so I can understand how to get the answer..

jeka94

To find 5/12-3/8, you have to find a common denominator. A common denominator of 12 and 8 could be 24. So, you multiply 5/12, both the numerator and the denominator by 2, which gives you 10/24. Then, you multiply 3/8 both by 3 to get the common denominator of 24. 3/8x 3 is 9/24. So, 10/24-9/24 is 1/24 because you only subtract the numerator and keep the denominator the same.

4 0

3 years ago

(X^2+y^2+x)dx+xydy=0 Solve for general solution

aksik [14]

Check if the equation is exact, which happens for ODEs of the form

$M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0$

if $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ .

We have

$M(x,y)=x^2+y^2+x\implies\dfrac{\partial M}{\partial y}=2y$

$N(x,y)=xy\implies\dfrac{\partial N}{\partial x}=y$

so the ODE is not quite exact, but we can find an integrating factor $\mu(x,y)$ so that

$\mu(x,y)M(x,y)\,\mathrm dx+\mu(x,y)N(x,y)\,\mathrm dy=0$

is exact, which would require

$\dfrac{\partial(\mu M)}{\partial y}=\dfrac{\partial(\mu N)}{\partial x}\implies \dfrac{\partial\mu}{\partial y}M+\mu\dfrac{\partial M}{\partial y}=\dfrac{\partial\mu}{\partial x}N+\mu\dfrac{\partial N}{\partial x}$

$\implies\mu\left(\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}\right)=M\dfrac{\partial\mu}{\partial y}-N\dfrac{\partial\mu}{\partial x}$

Notice that

$\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}=y-2y=-y$

is independent of x, and dividing this by $N(x,y)=xy$ gives an expression independent of y. If we assume $\mu=\mu(x)$ is a function of x alone, then $\frac{\partial\mu}{\partial y}=0$ , and the partial differential equation above gives

$-\mu y=-xy\dfrac{\mathrm d\mu}{\mathrm dx}$

which is separable and we can solve for $\mu$ easily.

$-\mu=-x\dfrac{\mathrm d\mu}{\mathrm dx}$

$\dfrac{\mathrm d\mu}\mu=\dfrac{\mathrm dx}x$

$\ln|\mu|=\ln|x|$

$\implies \mu=x$

So, multiply the original ODE by x on both sides:

$(x^3+xy^2+x^2)\,\mathrm dx+x^2y\,\mathrm dy=0$

Now

$\dfrac{\partial(x^3+xy^2+x^2)}{\partial y}=2xy$

$\dfrac{\partial(x^2y)}{\partial x}=2xy$

so the modified ODE is exact.

Now we look for a solution of the form $F(x,y)=C$ , with differential

$\mathrm dF=\dfrac{\partial F}{\partial x}\,\mathrm dx+\dfrac{\partial F}{\partial y}\,\mathrm dy=0$

The solution F satisfies

$\dfrac{\partial F}{\partial x}=x^3+xy^2+x^2$

$\dfrac{\partial F}{\partial y}=x^2y$

Integrating both sides of the first equation with respect to x gives

$F(x,y)=\dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3+f(y)$

Differentiating both sides with respect to y gives

$\dfrac{\partial F}{\partial y}=x^2y+\dfrac{\mathrm df}{\mathrm dy}=x^2y$

$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

So the solution to the ODE is

$F(x,y)=C\iff \dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3+C=C$

$\implies\boxed{\dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3=C}$

5 0

3 years ago

Use the quadratic formula to solve this equation to 3sf: 5x^2-2x-11=0

Rama09 [41]

X=1/5+2/5√14 or 1/5 + -2/5√14

7 0

3 years ago

Read 2 more answers

Alaina is making a birdseed mix with 2 1/3 lb sunflower seeds, 5/6 lb cracked corn, and 1/6 lb peanuts. How much cracked corn do

Darya [45]

Answer:1.25

Step-by-step explanation:

If you add everything it makes 3 and 1/3 pounds you want 5

If you divide 5 by 3 and 1/3 it's 1.5

Then you just need to multiply 5/6 by 1.5

7 0

3 years ago

Many poker games start with each player being dealt five cards, called the player's "hand". Remember, there are 52 cards in a st

jek_recluse [69]

Answer:

The number of different possible poker hands is found by counting the number of ways that 5 cards can be selected from 52 cards, where the order is not important. It is a combination, so we use c n r

Step-by-step explanation:

The possible number of the poker hands is probably . C 52 5= 52!/5!x47!= 2598960

5 0

3 years ago