2000
1box = 1400/7 = 200
200×3=600
1400+600=2000
Step-by-step explanation:
Given :Workers have packed 1,400 glasses in 7 boxes.
To Find :If they pack 3 more boxes, how many glasses will they have packed in all?
Solution:
Workers packed no. of glasses in 7 boxes = 1400
Workers packed no. of glasses in 1 box =
Workers packed no. of glasses in 3 boxes =
=
So, initially they packed 1400 glasses
If they pack 3 more boxes so, the pack 600 glasses more
So, The total no. of glasses have packed by workers = 1400+600 = 2000
Hence they have packed 2000 glasses in all.
Si el día es jueves, entonces el mañana del pasado mañana de ayer de ayer es martes.
<h3>Definición del día mediante equivalencia aritmética</h3>
Sea el día <em>actual</em> (<em>lunes</em>) el día 0, el día <em>anterior</em> tiene equivalencia de -1 y el día <em>posterior</em> tiene equivalencia de +1. A continuación, traducimos matemáticamente la expresión:
<em>Si el anteayer (-2) del pasado mañana (+2) de mañana (+1) del ayer(-1) el mañana (+1) de hace 2 días (-2) es el pasado mañana (+2) del mañana (+1) del mañana (+1) del anteayer (-2) del mañana (+1) del lunes (0). ¿qué día es el mañana (+1) del pasado mañana (+2) de ayer (-1) de ayer (-1)?</em>
<h3>Simplificación</h3>
<em>Si (-1) es (+3). ¿Qué día es (+1)?</em>
Si el día es jueves, entonces el mañana del pasado mañana de ayer de ayer es martes.
Para saber más de acertijos matemáticos, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/24613771
Answer: I think the answer is 1011.84. Hope this helps. Can you give me brainliest
Step-by-step explanation:
We will get the number of possible selections, and then subtract the number less than 25 cents.
We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.
That's 5*4*3 = 60 selections
Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels.
To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2 on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).
If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.
And there is 1 other selection less than 25 cents, 2 dimes and no nickels.
So that's 4+3+1 = 8 selections which we must subtract from the 60.
Answer 60-8 = 52 selections of coins worth 25 cents or more.
Answer:
See I don't know the Answer but I Need points to ask question so Sorry
Step-by-step explanation:
