Answer:
7/12 in exact form
Step-by-step explanation:
I think you just multiply the numerator by the resipical of the denominator.
14.29 * .0725 = 1.04
1.04 * 3 = 3.12
Answer:
V2=-20.0155m/s
Step-by-step explanation:
To answer this question we will use the principle of conservation of momentum which is
MtVt=M1V1+M2V2
1) let's find the initial velocity.
We will use,
v=a*t
v=10m/s2*2s = 20 m/s
d=vot+1/2*a*t2
d=0+1/2*10*4
d=20m
2) For the speed of the lighter piece we use,
v22=v12+2ad
0=v12+2*-9.81*(530-20)
v12=10006.2
v1=100.031m/s
3) Computing this in our conservation of momentum equation it will be-
MtVt=M1V1+M2V2
1500kg*20m/s=(1500*1/3)kg*100.031m/s + (1500*2/3)+V2
30000=50015.5+1000V2
Therefore V2=-20.0155m/s.
Answer:
x=1/9
Step-by-step explanation:
Answer:
1. multiply 32 on both sides to get rid of the fraction
which leaves you with
68≤1-u
2. You can add the U to one side and subtract 68 from the other side
which leaves you with
u≤-67
