Answer:
12
Step-by-step explanation:
Answer:
I'm going to lay this out in a chart so it's a little easier to see:
F(x) = f(g(x))
x | f (x) | f ' (x) | g (x) | g ' (x)
--------------------------------------
-2 | 8 | 4 |
5 | | 3 | -2 | 6
Remember the chain rule, which says
(f (g (x))) ' = g ' (x) f ' (g (x))
When they ask for F ' (5), they are asking for (f (g (x))) ' when x = 5.
Using the chain rule, that's
F ' (5) = g ' (5) f ' (g (5))
We can simplify using the numbers provided.
F ' (5) = (6) f ' (-2)
F ' (5) = (6) (4)
F ' (5) = 24
I hope that helps!
by jannat <33
9514 1404 393
Answer:
| 573 |
Step-by-step explanation:
The product of a 1×2 matrix and a 2×1 matrix will be a 1×1 matrix. The value of the only term will be the dot-product of the row of the first matrix and the column of the second matrix.
P = | 17·27 +19·6 | = | 573 |
Answer:
(a)18
(b)1089
(c)Sunday
Step-by-step explanation:
The problem presented is an arithmetic sequence where:
- First Sunday, a=1
- Common Difference (Every subsequent Sunday), d=7
We want to determine the number of Sundays in the 120 days before Christmas.
(a)In an arithmetic sequence:

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.
Therefore, Aldsworth advertised 18 times.
(b)Next, we want to determine the sum of the first 18 terms of the sequence
1,8,15,...

The sum of the numbers of days published in all the advertisements is 1089.
(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.