Answer: A. 4p + $17.50 = $53.50; p = $9.00
1: 17.50+4p= Nothing further can be done with this topic. Please check the expression entered or try another topic.
17.5
+
4
p
2: 4p=53.50-17.50= 4p=53.50-17.50
Step-by-step explanation: 9
The total bill: $53.50
17.50 + 4 x = 53.50
4 x = 53.50 - 17.50
4 x = 36
x = 36 : 4
x = $9
Answer: The price of each shrub is $9.
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Answer:
$9
Step-by-step explanation:
Let be the price of each shrub.
4 shrubs at each costs dollars
Potting soil is $17.50
Hence, total cost is the expression
We know that total bill is $53.50, so we can equate it to the expression:
This equation can be solved for to find cost of each shrub.
Solving for gives us:
So price of each shrub is $9
Answer:
x = 9
y = 9
Step-by-step explanation:
Given :
Let :
Kenyan French roast coffee = x
Cost per x = $8
Sumatran Coffee = y
Cost per y = $10
x + y = 18 - - - - (1)
8x + 10y = 9 * 18 ;
8x + 10y = 162 - - - - (2)
From (1):
x = 18 - y
Put x = 18 - y in (2)
8(18 - y) + 10y = 162
144 - 8y + 10y = 162
2y = 162 - 144
2y = 18
y = 9
x = 18 - y
x = 18 - 9
x = 9
Answer: Heyaa! ~
10. 8√2
11. 2h²√3
12. 2h³√5k⁴
Step-by-step explanation:
<em>- Lets solve it together! </em>
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.
Hopefully this helps you!
Answer:
In the explanation
Step-by-step explanation:
Going to start with the sum identities
sin(x+y)=sin(x)cos(y)+sin(y)cos(x)
cos(x+y)=cos(x)cos(y)-sin(x)sin(y)
sin(x)cos(x+y)=sin(x)cos(x)cos(y)-sin(x)sin(x)sin(y)
cos(x)sin(x+y)=cos(x)sin(x)cos(y)+cos(x)sin(y)cos(x)
Now we are going to take the line there and subtract the line before it from it.
I do also notice that column 1 have cos(y)cos(x)sin(x) in common while column 2 has sin(y) in common.
cos(x)sin(x+y)-sin(x)cos(x+y)
=0+sin(y)[cos^2(x)+sin^2(x)]
=sin(y)(1)
=sin(y)
Relatively prime means there are no number greater than 1 that divides them both.
Find the GCF for each set:
A. 68 and 119
68: 1 , 2, 4, 17, 34,68
119: 1, 7, 17
Both numbers can be divided by 1 or 17 so are not relative.
B.
40 and 395
are both divisible by 1 and 5 so are not relative.
C. 119 and 715
Are both only divisible by 1, so are relative.
D. 63 and 56
Are divisible by both 1 and 7 so are not relative.
The answer is C. 119 and 715
