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ra1l [238]
3 years ago
7

In trapezoid TRAP, the parallel bases are TP and RA

Mathematics
1 answer:
Westkost [7]3 years ago
5 0

9514 1404 393

Answer:

  UV is not the midline. (The midline length is 4.5.)

Step-by-step explanation:

The trapezoid midline is the average of the lengths of the bases. Here, the midline length would be ...

  (7 ft +2 ft)/2 = (9 ft)/2 = 4.5 ft

The line length shown is 3.5 ft, so the segment shown is not the midline.

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Use the zero product property to find the solutions to the equation x^2+x-30=12
lukranit [14]

Answer:

Due to there being no negatives in this equation, you can pretty much just eliminate the first 3 answers.


However in working out, here is what I did.

x^2 + x - 30 = 12 (+30) 

= x^2 + x = 42


Then you can conclude that the answer is D, due to 6 x 6 = 36, plus 7 equaling 42. 





8 0
3 years ago
The slope intercept for of the equation of a line that passes through point (-2,-13) is y=5x-3. What is the pint slope form of t
siniylev [52]
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NEED MATH HELP ASAP
Dafna1 [17]

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2

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4 0
4 years ago
Solve by using square root: <br> 4(x-1)^2+2=10
Scilla [17]
4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}

Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}


3 0
3 years ago
Read 2 more answers
What is 2/5 divided by 3/4
Triss [41]
It’s 8/15 decimal form it’ll be 0.53 hope this helped !
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3 years ago
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