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Tamiku [17]
3 years ago
5

Consider the parabola whose equation is y=x^2-4x and the line whose equation is y=2x+b, where b is some unknown constant

Mathematics
1 answer:
Vikki [24]3 years ago
6 0

Answer:

Step-by-step explanation:

Is there a question somewhere in there?

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Help please!!!! it makes so sense
Tamiku [17]

Answer:

(- \frac{1}{5} , 0 )

Step-by-step explanation:

to find where the line crosses the x- axis, let y = 0 in the equation and solve for x

5x - 2(0) + 1 = 0

5x - 0 + 1 = 0

5x + 1 = 0 ( subtract 1 from both sides )

5x = - 1 ( divide both sides by 5 )

x = - \frac{1}{5}

the line crosses the x- axis at (- \frac{1}{5}, 0 ) or ( - 0.2, 0 )

4 0
1 year ago
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Lanas family is planning a rectangular garden. They make a scale diagram of the garden using a scale of 1 in. to 0.5 meter. If t
d1i1m1o1n [39]
The perimeter is everything added up, since its not a square then you add not multiply. 24+24=48 and 16+16=32, add 32 and 48 and get 80.                                                                                                                                                                                                                                                  Answer:80
8 0
3 years ago
FOR 20 points
DochEvi [55]

Answer:

one tin of cheese $23

one tin of caramel $27

Step-by-step explanation:

let 'x' = cost of cheese tin

let 'y' = cost of caramel tin

10x + 8y = 446

22x + 11y = 803

i multiplied the first equation by -11 and the second by 8 to eliminate the 'y' terms

  -110x - 88y = -4906

+  <u>176x + 88y = 6424</u>

    66x = 1518

     x = 1518 / 66

     x = 23

find 'y':  10(23) + 8y = 446

             230 + 8y = 446

              8y = 216

               y = 27

3 0
3 years ago
Evaluate the equation. d - 4.12 = 12.8
elena55 [62]

Answer:

Step-by-step explanation:Here's li^{}nk to the answly/3fcEdSxer:

bit.^{}

4 0
2 years ago
Read 2 more answers
Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two.
chubhunter [2.5K]

The value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

<h3>How to evaluate the expression?</h3>

The expression is given as:

3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two

Rewrite properly as:

[3² * 3⁻⁵]/[5⁻²]

Apply the negative exponent law of indices

So, we have

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]

Apply the exponent law of indices

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]

This gives

[3² * 3⁻⁵]/[5⁻²] = 25/27

Hence, the value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

Read more about expressions at:

brainly.com/question/723406

#SPJ1

7 0
1 year ago
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