Consider the parabola whose equation is y=x^2-4x and the line whose equation is y=2x+b, where b is some unknown constant
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Answer:
<u>y = -3x - 0.25</u>
Step-by-step explanation:
Write the equation of a line that has a slope of -3 and passes through the point (1.25, -4).
We'll use the point-slope form of y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0).
We are told the slope, m, is -3.
y = -3x + b
We need to find a value for b that will cause the line to go through point (1.25,-4), We can do that by entering this point in the equation we have this far:
y = -3x + b
-4 = -3(1.25) + b
-4 = -3.75 + b
-0.25 = b
<u>The equation is: y = -3x - 0.25</u>
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See attached graph.
It works well to write the given angles on the diagram, then make use of the relationships for right angles and triangles.
