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Alona [7]
3 years ago
6

There are 28-right handed students in a class of 31. What is the probability that a student chosen at a random time will be left

handed?
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0
<span>There are 28 right handed students out of 31 total. So there are 31 - 28 = 3 left handed students. 

The probability of choosing a left handed student is 3/31.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
DENIUS [597]3 years ago
5 0

Answer: \dfrac{3}{31}

Step-by-step explanation:

Given: The number of right handed students = 28

The total number of students = 31

The number of left handed students = 31-28=3

Now, the probability that a student chosen at a random time will be left handed is given by :-

\text{P(Left)}=\dfrac{\text{Number of left handed students}}{\text{Total number of students}}\\\\\Rightarrow\text{P(Left)}=\dfrac{3}{31}

Hence, the probability that a student chosen at a random time will be left handed is \dfrac{3}{31}

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Explanation:

The function is y>-\frac{1}{3} x+5

To graph the function, let us find the x and y intercepts.

To find x-intercept, let us substitute y=0 in the function y>-\frac{1}{3} x+5

\begin{aligned}0 &=-\frac{1}{3} x+5 \\-5 &=-\frac{1}{3} x \\x &=15\end{aligned}

Thus, the x-intercept is (15,0)

To find the y-intercept, let us substitute x=0, we get,

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Thus, the y-intercept is (0,5)

The graph has no asymptotes.

To plot the points in the graph, we need to substitute the values for x in the function y>-\frac{1}{3} x+5, to find the y-values.

The points are (-2,5.667),(-1,5.333),(1,4.667),(2,4.333),(3,4). The image of the graph and table is attached below:

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