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Dahasolnce [82]
3 years ago
14

If you have 3.0 liters of an unknown gas, at standard temperature and pressure conditions, then you can calculate what about tha

t gas?
Chemistry
1 answer:
Mariana [72]3 years ago
8 0
We assume it as an ideal gas therefore we can use the ideal gas equation to solve the problem. The ideal gas equation is expressed as PV = nRT. We are given the volume, temperature and pressure. Therefore, we can solve for the amount of the gas in moles.
<span>
n = PV / RT
n = </span>1.00(3L) / (<span>0.08206 atm L/mol K ) 273 K
n = 0.1339 mol

</span><span>
</span>
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Answer:

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4 0
3 years ago
If 211 mL of water is added to 5.00 mL of 3.24 M NaCl solution,
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Answer:

0.075M

Explanation:

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Concentration=\frac{Mass \ Solute}{Volume \ of \ Solution}

-We the solve the molarity problem as follows:

M_1V_1=M_2V_2\\\\V_2=V_1+211=211+5=216mL\\\\\therefore M_2=\frac{M_1V_1}{V_2}\\\\=\frac{3.24\times 5}{216}\\\\\\=0.075\ M

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6 0
4 years ago
Given the general chemical equation 3A + 2B → C + 5D,
Irina-Kira [14]

Answer :

(a) The number of moles of D produced can be, 6.67 moles.

(b) The volume of D prepared can be, 24.5 L

Explanation :

The given chemical reaction is:

3A+2B\rightarrow C+5D

Part (a) :

From the balanced chemical reaction, we conclude that:

As, 3 moles of A react to give 5 moles of D

So, 4 moles of A react to give \frac{5}{3}\times 4=6.67 moles of D

Thus, the number of moles of D produced can be, 6.67 moles.

Part (b) :

As we know that 1 moles of substance occupies 22.4 L volume of gas.

As, 2\times 22.4L volume of B gives 5\times 22.4L volume of D

As, 9.8 L volume of B gives \frac{5\times 22.4L}{2\times 22.4L}\times 9.8L=24.5L volume of D

Thus, the volume of D prepared can be, 24.5 L

4 0
3 years ago
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givi [52]

Answer: 51.9961 g/mol, don't know if it helps :)

Explanation:

7 0
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