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emmainna [20.7K]
3 years ago
14

An ordered list of chemical substances is shown.

Chemistry
1 answer:
Alex73 [517]3 years ago
3 0

answer : the correct option is, (B) 2, 3 and 6.

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In the front of the room, there is a bottle that contains a 32.00 g sample of sulfur. This is
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6.02x10^23 atoms is the answer
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55.99 mols of nickel carbonyl produces how many grams of nickels?
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3286 grams

Explanation:

For every mol of Ni(CO)4 reactant, a mol of Ni is produced (55.99 mol). Multiply this by the molecular mass of Ni (58.69 g/mol) to give 3286 grams

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Does a sharpener have kinetic energy ?
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A student was trying to determine the mole percent of A in a mixture of A and B using refractive index. If their mixture has a r
Elina [12.6K]

Explanation:

Formula to calculate refractive index of n is as follows.

     n = X_{A} \times n_{A} + X_{B} \times n_{B}

where,    X_{A} = mole fraction of A

              X_{B} = mole fraction of B

              n_{A} = refractive index of A

              n_{B} = refractive index of B

Hence, putting the given values into the above formula as follows.

         n = X_{A} \times n_{A} + X_{B} \times n_{B}

         1.5248 = X_{A} \times 1.7058 + X_{B} \times 1.3658 ........ (1)

Also, it is known that X_{A} + X_{B} = 1

and,          X_{B} = 1 - X_{A} ......... (2)

Now, put equation (2) in equation (1) as follows.

        1.5248 = X_{A} \times 1.7058 + 1 - X_{A} \times 1.3658  

        1.5248 = X_{A} \times 1.7058 + 1.3658 - 1.3658X_{A}  

         X_{A} = 0.467

And, the value of  X_{B} is calculated as follows.

            X_{B} = 1 - X_{A}

                       = 1 - 0.467

                       = 0.533

Hence, mole percentage of A will be calculated as follows.

      Mole % of A = \frac{n_{A}}{n_{A} + n_{B}}      

                            = \frac{0.467}{0.467 + 0.533} \times 100

                            = 46.7%

Thus, we can conclude that the mole percent of A in their mixture is 46.7%.

8 0
3 years ago
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