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olga nikolaevna [1]
3 years ago
12

What is the time traveled in seconds?

Physics
1 answer:
max2010maxim [7]3 years ago
7 0
The answer is 4s per in the total of Distance Of Kilometers.
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Irene was investigating the behavior of gases at certain conditions. Which would most likely cause an increase in the rate of co
kipiarov [429]

Answer:

Increase in temperature

Increase in pressure

Explanation:

For the rate of collisions to increase, It can happen in various ways

1. The gasses can be made to move faster: This can be done by increasing their temperature. An increase in the temperature of the gases directly relates to a corresponding increase in their kinetic energy. This means that the molecules of the gases can move with a greater velocity, which will increase collision rates.

2. The volume of the container can be reduced: Consider this; If the container is made smaller, the molecules of the gases will have less space to move about. This means that they will be bumping into the walls of the container more frequently. This reduction in volume leads to an increase in the pressure of the gas. This is exactly what happens in a piston-cylinder assembly

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4 years ago
A hilly road is spiral in shape.​
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I- wym incorrect answer i-
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3 years ago
How much work does the electric field do in moving a -7.7 hC charge from the ground to a point whose potential is +55 V higher?
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I really don’t know I just need some points to help me though this test I’m very sorry
7 0
3 years ago
30 POINTS PLZ HELP!!!
Katyanochek1 [597]

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5 0
3 years ago
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n the figure, a uniform ladder 12 meters long rests against a vertical frictionless wall. The ladder weighs 400 N and makes an a
Leto [7]

Since the ladder is standing, we know that the coefficient of friction is at least something. This [gotta be at least this] friction coefficient can be calculated. As the man begins to climb the ladder, the friction can even be less than the free-standing friction coefficient. However, as the man climbs the ladder, more and more friction is required. Since he eventually slips, we know that friction is less than what's required at the top of the ladder.

 

The only "answer" to this problem is putting lower and upper bounds on the coefficient. For the lower one, find how much friction the ladder needs to stand by itself. For the most that friction could be, find what friction is when the man reaches the top of the ladder.

Ff = uN1

Fx = 0 = Ff + N2

Fy = 0 = N1 – 400 – 864

N1 = 1264 N

Torque balance

T = 0 = N2(12)sin(60) – 400(6)cos(60) – 864(7.8)cos(60)

N2 = 439 N

Ff = 439= u N1

U = 440 / 1264 = 0.3481

3 0
3 years ago
Read 2 more answers
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