A pivot clip is positioned at the center of a meter stick with two hanging clips placed on the left side (each clip is 5 g) one
at 10 cm from the center and other at 30 cm from the center. Each added mass is 30 g. What single mass would need to be positioned at 40 cm to the right of center to balance the system
1 answer:
Answer: 5grams
Explanation:
Using the principle of moment to solve the question which states that the sum of clockwise moments is equal to the sum of anticlockwise moments
And moment = Force × Perpendicular distance from the direction of the force
*Check attachment for diagram
Taking moment about the pivot placed at C,
Sum of anticlockwise moments = (5×30) + (5×10)
Clockwise moment = M×40
Equating both and getting M
(5×30) + (5×10) = M×40
150+50 = 40M
200 = 40M
M = 5g
The single mass is 5grams.
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