The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
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Velocity of the boy at the bottom of the slide</h3>
The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- h is height of the boy
- g is acceleration due to gravity
v = √(2 x 9.8 x 10)
v = 14 m/s.
Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
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To solve this problem we will apply the concepts related to the conservation of momentum. By definition we know that the initial moment must be equivalent to the final moment of the two objects therefore


Here,
Mass of each object
Initial velocity of each object
= Final velocity of each object
Since the initial velocity relative to the metal tank is at rest, that velocity will be zero. And considering that in the end, the speed of the two bodies is the same, the equation would become

Rearranging to find the velocity,

Replacing we have that,


Therefore the velocity of the shark immediately after it swallows the tank is 
Answer:
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Fastener because a fastener is something that connects to objects and usually can come apart but can also be permanent
The mass of the car [m] = 1.2×10^3 kg.
The initial speed of car[u]= 0 m/s
The final speed of car [v]= 20 m/s
We are asked to calculate the force required to increase the speed from 0 to 20 m/s.
The momentum of a substance is defined as product of mass and velocity.
Mathematically momentum p=m×v [Here m is the mass]
From Newton's second law we know that-

[here t is the time]



[ANS]
Hence the correct answer to the question is C.