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Dafna1 [17]
3 years ago
7

It is known that 5% of the population over the age of 30 in a city is a university graduate. Among the 100 people chosen randoml

y; a) Possibility to be 5 university graduates b) What is the likelihood of never being a university graduate?
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
5 0

Answer:

A) 1/3200000

B) 19/20

Step-by-step explanation:

Percentage population of graduates = 5

Proportion of graduates from 100 random samples = percentage × number of samples

Proportion of graduates = 0.05 × 100 = 5

Probability of having 5 graduates among the 100 random samples:

P(1 graduate) = possible outcome / total required outcome

P(1 graduate) = (5 / 100) = 1/20

P(5 graduates) = (1/20)^5

P(5 graduates) = 1/3200000

Probability of never being a graduate = (1 - probability of being a graduate)

Probability of never being a graduate = ( 1 - (1/20)) = 19/20

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Answer:

The most common salary is $605. The salary that half the employees salaries surpass is $630. The percent of employees salary that serve because $700 is 75%. Percent of employees salaries that were less than $480 is 25%. The 9% percent of employees salaries this surpass $891 years. The total weekly salary of 104 employees is 57200.

Step-by-step explanation:

It is given that mean is $550, first quartile is $480,  median is $630, third quartile is $700,  mode is $605 and 91st percentile is $891.

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The mode of a set of data values is the value that occurs most often.

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The percent of employees salaries this surpass $891 years is 9%. Because $891 is 91 percentile. Therefore 9% employees get more than $891.

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because means is $550, therefore the total weekly salary of 104 employees is 57200.

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