The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
for GM, you find out the square root of the product of the numbers provided.
since 72 can be broken down into the product of 36 and 2. 6 being the square root of 36 comes out, leaving 2 behind.
Answer:
x = 59°
y = 67°
Step-by-step explanation:
x = y - 8
x + y + 54 = 180
(y - 8) + y = 180 - 54
2y - 8 = 126
2y = 134
y = 67°
x = 59°
Step-by-step explanation:
