Answer:
Aircraft 1 has 194 seats, Aircraft 2 has 126 seats, and Aircraft 3 has 82 seats.
Step-by-step explanation:
In order to solve the present problem, an equation must be formulated. Thus, if the first aircraft has 68 seats more than the second one, and the third one has 44 fewer seats than the second aircraft, we can establish the following values:
Aircraft 1: X + 68
Aircraft 2: X
Aircraft 3: X - 44
Therefore, the equation could be stated as follows:
X + 68 + X + X - 44 = 402
3X = 402 + 44 - 68
3X = 378
X = 378/3
X = 126
So, Aircraft 1 will have 194 seats (126 + 68), Aircraft 2 will have 126 seats, and Aircraft 3 will have 82 seats (126 - 44).
