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marysya [2.9K]
3 years ago
9

What is the solution to -4|-2x+6| = -24

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0
X = 0.  Since the absolute value of -2x+6 is 2x+6, the absolute value sign acts as () so it would be -4(2x+6) = -24.  That would come out to be           -8x -24 = -24.  Using proper algebra, the answer would come out to be 0
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What is the answer to <br> 5/6 + -4/9 - -2
barxatty [35]

Answer:

The answer is 2.38888888889.

Step-by-step explanation:

Hope this helps! ^w^

5 0
2 years ago
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Felix's parents opened a savings
Crazy boy [7]

The money in the Felix's account will be $6798 when he is 21.

<u>Step-by-step explanation:</u>

It is given that,

  • The amount deposited is $2000.
  • The account earns 6%  compound interest.
  • It is compounded  annually for 21 years.

<u>To find the money in Felix's account after 21 years :</u>

The formula used here is,

⇒ A = P(1+r/n)^{nt}

where A is the amount after 21 years.

  • P is the initial amount deposited ⇒ P = 2000
  • r is the rate ⇒ r = 0.06
  • n is the number of times interest is compounded per year⇒ n = 1
  • t is the time period ⇒ t = 21

⇒ 2000(1+0.06/1)^{21\times 1}

⇒ 2000(1.06)^{21}

⇒ 2000\times3.399

⇒ 6798

Therefore, The money in the Felix's account will be $6798 when he is 21.

4 0
3 years ago
Need help asap 8 points
lubasha [3.4K]
Question 13 is 14 x is 14
7 0
3 years ago
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Simplify each answer into a fraction, Please show work as well!
scoray [572]

Answer: 1) 8/15 2) 2 4/9 3) -13/45

Step-by-step explanation:

1/5 + 1/3 = 6/30 + 10/30 = 16/30 = 8/15

2 1/9 + 1/3 = 19/9 + 3/9 = 22/9 = 2 4/9

1/9 - 2/5 = 5/45 - 18/45 = -13/45

7 0
2 years ago
A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish
Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or \frac{x}{y}=\frac{333}{444}

⇒ \frac{x}{y}=\frac{3}{4}

⇒ y = \frac{4x}{3} --------(1)

Similarly x' : y' = 333 : 444

⇒ \frac{x'}{y'}=\frac{333}{444}

⇒ \frac{x'}{y'}=\frac{3}{4}

⇒ x' = \frac{3y'}{4} ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

\frac{x+y}{x'+y'}=\frac{464646}{555}

Now we replace the values of x and y' from equation (1) and equation (2)

\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}

\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}

\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}

\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}

\frac{x}{y'}=\frac{232323}{370}

\frac{y'}{x}=\frac{370}{232323}

\frac{y'}{x}=\frac{10}{6279}

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0
3 years ago
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