C - (x-3)^2=36
If we expand (x-3)^2=36:
(x-3)(x-3)=36
x^2-3x-3x+9=36
x^2-6x+9=36
Then subtract 36
x^2-6x-27=0
Answer:
51
Step-by-step explanation:
11+(-7)^2-9 - original
11+49-9 - square the -7, since its in brackets the negative applies too and a negative x a negative = positive, so it ends up as 7x7+49
60-9 - add both positives 11+49=60
51 - subtract 9 from 60, 60-9=51
Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
The answer would be (-2,10)
Explanation:
Since it is telling us to focus on point A, we should do so.
It tells us to shift -6 units horizontally. This means we should shift point A to the left 6 units.
Then it wants us to reflect over the x-axis. The x-axis is the horizontal line. Flipping it across just means changing the x value to the opposite.
Therefore it is (-2,10)
