2 answers:
Answer:
zero
Step-by-step explanation:
If the same sum is received for the sale of 20 apples at price p as is received for the sale of 140 apples at price p, then we must have ...
20p = 140p
120p = 0 . . . . . . subtract 20p
p = 0 . . . . . . . . . divide by 120
The price was zero.
Answer:
- Price was 1 unit of money per each 7 apples and 3 units of money per each extra apple
- Each woman received 20 unit of money
Step-by-step explanation:
This is the tricky one
I think 'The Seven Apple' is the hint. Let's see what the numbers have to do with 7:
- 20 = 7*2 + 6
- 40 = 7*5 + 5
- 60 = 7*8 + 4
- 80 = 7*11 + 3
- 100 = 7*14 + 2
- 120 = 7*17 + 1
- 140 = 7*20 + 0
Assume each '7 apples' sold for a fixed price x and each 'extra' apple sold for a different price y. Since all add up to make same amount, we get:
- 2x + 6y = 5x + 5y = ... = 20x
Let x = 1, then we get y = 3
<u>So we get the sold price:</u>
- 20 apples cost: 2*1 + 6*3 = 20
- 40 apples cost: 5*1 + 5*3 = 20
- ...
- 140 apples cost: 20*1 = 20
So each apple woman got 20 units of money for their apples.
Price was 1 unit of money per each 7 and 3 units of money per each extra apple
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Step-by-step explanation: Reduce the expression, if possible, by cancelling the common factors.
