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3 years ago

How do you answer this?

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

6 0

The answer is c that’s the best answer

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5(x-3)+2x+21=3(x+4)+2x

nekit [7.7K]

Answer:

x = 3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

5(x−3)+2x+21=3(x+4)+2x

(5)(x)+(5)(−3)+2x+21=(3)(x)+(3)(4)+2x(Distribute)

5x+−15+2x+21=3x+12+2x

(5x+2x)+(−15+21)=(3x+2x)+(12)(Combine Like Terms)

7x+6=5x+12

Step 2: Subtract 5x from both sides.

7x+6−5x=5x+12−5x

2x+6=12

Step 3: Subtract 6 from both sides.

2x+6−6=12−6

2x=6

Step 4: Divide both sides by 2.

Hope this helps!

3 0

3 years ago

Mr. Petersons rectangular garden had a width of 3 meters and an area of 10 square meters. This year he wants to make the garden

lesya692 [45]

Answer:

Measurements of this years garden are 10 meters and 6 metres.

Step-by-step explanation:

Width of a rectangular garden = 3 meters

Area of a rectangular garden = 10 square meters

Also,

Area of a rectangular garden = length × breadth

10 = length × 3

Length = $\frac{10}{3}$ meters

Mr. Petersons wants to make the garden three times as long and two times as wide.

New length = 3 (length) = $3(\frac{10}{3} )=10$ meters

New breadth = 2(width) = 2(3) = 6 meters.

Therefore,

Measurements of this years garden are 10 meters and 6 metres.

8 0

3 years ago

A typical lap around a track in the United States has length of 440 yards. How many lap would need to be complete to run a mile?

g100num [7]

4 laps because a mile is 1,760 yards and the 440 laps need to be divided into 1,760 so 1,760/440 is 4 so four laps are needed to complete a mile

3 0

3 years ago

What percent of a present amount of radioactive radium (226Ra) will remain after 1200 years? The half life of 226Ra is 1599 year

sp2606 [1]

Answer:

59.44%

Step-by-step explanation:

$M_{R} = \frac{M_{O} }{2^{n} }$

$n=\frac{t}{t\frac{1}{2} }$

Where $M_{R}$ = mass remaining

$M_{O}$ =original mass.

t= time

$t\frac{1}{2}$ =half life

$t\frac{1}{2}$ =1599, t= 1200, $M_{O}$ =226, $M_{R}$ =?

$n=\frac{1200}{1599}$

n= 0.750469

$M_{R} = \frac{226}{2^{ 0.750469} }$

$M_{R}$ =134.3367amu

percentage of mass remaining = $\frac{134.3367amu}{226amu}$ *100%

= 59.44%

8 0

3 years ago

Question 6 of 10

Marizza181 [45]

B is the right answer
f(x) = x-3
y= x-3
x= y-3
x+3 =y
f^-1(x) = x+3

5 0

3 years ago