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Vesna [10]
3 years ago
15

If a metallic wire is stretched regularly so that its length increased to the double,

Physics
1 answer:
Travka [436]3 years ago
5 0

Answer:

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Explanation:

scjigbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbefvuabddddddddaaetaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaatttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttgbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbuyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

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2. If you exert a force of 10.0 N to lift a box a distance of 0.9 m, how much work have you done?
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<span> force of 10.0 N
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<span>distance of 0.9 m
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In which of the following wave types is the particle motion parallel to wave motion?
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WHICH OF THE FOLLOWING IS EQUIVALENT TO 700 MILLILITERS?
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its A
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What is the Celsius eguivalent of 212°F?<br> 32°C<br> 0°C<br> 100°C<br> 212°C
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A piece of Nichrome wire has a radius of 7.1 x 10-4 m. It is used in a laboratory to make a heater that dissipates 3.20×102 W of
bekas [8.4K]

Answer:

the length of the Nichrome wire is <em>59.88 m</em>

<em></em>

Explanation:

The resistance of a wire is determined by:

P = V² / R                              or    R = V² / P

where

  • V is the voltage
  • R is the resistance
  • P is the power

We also know that

R = PL / A

where

  • A is the area and it is equal to πr²
  • P = 3.20 × 10² W

Therefore, the length of the Nichrome wire is

L  = RA / ρ

L = (V²/P)(πr²) / ρ

L = V²πr² /  ρ P

L = (110 V)²(π)(7.1 × 10⁻⁴ m)² / (3.2 × 10² W)(100 × 10⁻⁸ Ω·m)

<em>L = 59.88 m</em>

7 0
4 years ago
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