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Grace [21]
4 years ago
13

Dolphins emit clicks of sound for communication and echolocation. A marine biologist is monitoring a dolphin swimming in seawate

r where the speed of sound is 1522 m/s. When the dolphin is swimming directly away at 7.2 m/s, the marine biologist measures the number of clicks occurring per second to be at a frequency of 2674 Hz. What is the difference (in Hz) between this frequency and the number of clicks per second actually emitted by the dolphin?
Physics
1 answer:
LenKa [72]4 years ago
6 0

Answer:

12.64968 Hz

Explanation:

v = Velocity of sound in seawater = 1522 m/s

u = Velocity of dolphin = 7.2 m/s

f' = Actual frequency = 2674 Hz

From Doppler effect we get the relation

f=f'\frac{v-u}{v}\\\Rightarrow f=2674\frac{1522-7.2}{1522}\\\Rightarrow f=2661.35032\ Hz

The frequency that will be received is 2661.35032 Hz

The difference in the frequency will be

2674-2661.35032=12.64968\ Hz

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Answer: 2.73m/s

Explanation:

Potential energy of the water is turned into kinetic energy

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d = depth of the water = 0.38m

v = velocity of leaking water

m × 9.81 × 0.38 = mv^2/

eliminate m on both sides and multiply through by 2

7.4456 = v^2

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v = 2.73m/s

3 0
3 years ago
Which formula represents Snell’s law?
inysia [295]

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6 0
3 years ago
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Given the resistivities below, which matedal is best described as an insulator?
Karolina [17]

Answer:

C. 3.2 x 10^8 Ω•m

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3.2 x 10^8 Ω•m

6 0
4 years ago
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he result of this is that adiabatic systems are highly effective in hot, dry environments, while using less water than traditional evaporative units. Adiabatic units also deliver the required cooling capacity in a smaller footprint and/or lower fan motor horsepower than a completely dry cooler/condenser.

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However, we know from Newton's second law that F = ma. Therefore, force will increase or decrease proportionally with mass. This means if an object maintains a contestant acceleration and its mass doubles, the force that it provides will also double. 
3 0
3 years ago
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