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elena55 [62]
3 years ago
7

Use the Rational Root Theorem to list all possible rational roots for the equation.

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
The answer would be B and here’s the steps :)

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The number 27 is a perfect cube. 3 times 3 times 3 equals 27. find four other numbers that are perfect cubes and two numbers tha
yKpoI14uk [10]

Answer:

Numbers that aren't: 35 and 43. It can literally be any number.

Perfect cubes: 8,64,125,216. You can find perfect cubes by cubing any number. For example 6^3 (6 to the power of 3) is 216. A perfect cube.

6 0
3 years ago
Read 2 more answers
My brain stopped. I need help
Alisiya [41]

Answer:

x = 99°

y = 91°

Step-by-step explanation:

For Cyclic quadrilateral, the sum of the opposite angles = 180°

Let's find x :-

x + 81° = 180°

x = 180 - 81

x = 99°

Let's find y :-

y + 89° = 180°

y = 180 - 89

y = 91°

Hope this helps you !

5 0
2 years ago
Which of the equations below could be the equation of this parabola?
nirvana33 [79]

Answer:

 y=-4x^2  is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

y=-4x^2

\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

x_v=\frac{0+0}{2}

x_v=0

\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=-4\cdot \:0^2

y_v=0

Therefore, the parabola vertex is

\left(0,\:0\right)

\mathrm{If}\:a

\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

a=-4

\mathrm{Maximum}\space\left(0,\:0\right)

so,

\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)

Therefore,  y=-4x^2  is the equation of this parabola. The graph is also attached.

7 0
3 years ago
0.64 as a fraction in lowest terms
Nezavi [6.7K]

16/25 is 0.64 as a fraction in lowest terms

5 0
3 years ago
Read 2 more answers
5x-6_&lt; -5x +16 <br> solve
Olegator [25]

Answer:

haha

Step-by-step explanation:

thanks for the points

4 0
3 years ago
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