Answer:
hi
Step-by-step explanation:
Answer:X=-15
Step-by-step explanation:
-4x/5=12
5x-4x/5=5x12
-4x=5x12
-4x=60
-4x/-4=60/-4
x=-15
Answer:
The number of trees at the begging of the 4-year period was 2560.
Step-by-step explanation:
Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was
, and for the next three years we have that
Start End
Second year
-------------- 
Third year
-------------
Fourth year
--------------
So the formula to calculate the number of trees in the fourth year is
we know that all of the trees thrived and there were 6250 at the end of 4 year period, then
⇒
Therefore the number of trees at the begging of the 4-year period was 2560.
Answer:
Step-by-step explanation:
hello :
hello :
1) divid by 3 : 27:9= 9/3
2) 9/3 = 3/1
Answer:
Two standard deviations
Step-by-step explanation:
The Z score is obtained using the mean and standard deviation, according to the empirical. Rule, which gives percentage of values that lie within an interval estimate in a normal distribution ;
one standard deviation lie within 68% of the mean
Two standard deviations lie within 95%
Three standard deviations lie within 99.7%
Hence, for the question given, 95% fall within 2 standard deviations of the mean